A is the correct answer, NOT c. You don't list elements of the domain each time they occur, you enter each element of the domain only once
We will use demonstration of recurrences<span>1) for n=1, 10= 5*1(1+1)=5*2=10, it is just
2) assume that the equation </span>10 + 30 + 60 + ... + 10n = 5n(n + 1) is true, <span>for all positive integers n>=1
</span>3) let's show that the equation<span> is also true for n+1, n>=1
</span><span>10 + 30 + 60 + ... + 10(n+1) = 5(n+1)(n + 2)
</span>let be N=n+1, N is integer because of n+1, so we have
<span>10 + 30 + 60 + ... + 10N = 5N(N+1), it is true according 2)
</span>so the equation<span> is also true for n+1,
</span>finally, 10 + 30 + 60 + ... + 10n = 5n(n + 1) is always true for all positive integers n.
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Answer:
e. All of these statements are true.
Step-by-step explanation:
The first statement is true because an experiment is actually the process by which an observation is made. Consider rolling a die. It is called an experiment because we observe which side of the die lands facing upwards and that number is noted.
The second statement is also true because a simple event is the one which can not be further decomposed into an event. (Compound events can be decomposed into simple events).
The third statement is also true that an event is the collection of one or more simple events. An event can contain either simple events of compound events which are basically a combination of two or more simple events.
Hence, we can say that <u>all the statements are true</u>.
Answer:
30 (.1)=3
or you could do
30×.1=3
you could use either one but I dont know what the person your turning the work in requires the equation to look like
Answer:
The answer is A.
Step-by-step explanation:
