Answer:
Determination of HYP,OPP,ADJ with respect to x.
<u>Opposite</u><u> </u><u>side</u><u> </u><u>of</u><u> </u><u>right</u><u> </u><u>angle</u><u>:</u><u>Hypotenuse</u><u>:</u><u> </u><u>AC</u>
<u>Opposite</u><u> </u><u>side</u><u> </u><u>of</u><u> </u><u>given</u><u> </u><u>angle</u><u>:</u><u> </u><u>Opp</u><u>:</u><u>BC</u>
<u>remaining</u><u> </u><u>side</u><u> </u><u>of</u><u> </u><u>a</u><u> </u><u>triangle</u><u>:</u><u> </u><u>Adjacent</u><u>:</u><u>AB</u><u>.</u>
I’m pretty sure it’s because you got the price wrong
Hello!
In this case, you are looking for a value of K so the left side of the equation is equal to the right.
The left side of the equation is K (3x - 2), and the right is 4 - 6x. To get the left side to equal the right, you can set K = -2. This is because of the <u>distributive property</u>: a number just outside of the parenthesis can distribute to everything in the parenthesis like so:
-2 (3x - 2) = (-2 * 3x) - (-2 * -2) = -6x + 4
Therefore, your answer is K = -2.
Hope this helps!
(Side note: a better way to do this would be to divide both sides by 3x - 2)
Is there a picture that goes with this?
Answer:
The coordinates of Q and S are;
(-5,8) and (1,-3)
Step-by-step explanation:
When we reflect a point with coordinates (x,y) across the y-axis, we get a new point with the coordinates (-x,y)
So (5,8) becomes (-5,8)
and (-1,-3) becomes (1,-3)
