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liq [111]
3 years ago
12

Andy is solving a quadratic equation using completing the square. If a step in the process results in = (x – 6)2, could the orig

inal quadratic equation be solved by factoring? Explain your reasoning.
Mathematics
2 answers:
Zarrin [17]3 years ago
7 0
<span>Yes, the equation can be solved by factoring. Using the given equation, take the square root of both sides. Both 169 and 9 are perfect squares, so the left side becomes plus or minus 13/3, which is rational. Six plus 13/3 is a rational number, and 6 minus 13/3 is also a rational number. If the solutions of a quadratic equation are rational, then the equation is factorable. </span>
UkoKoshka [18]3 years ago
4 0

Answer:

Both169 and 9 are perfect squares. The square root of 169/9 is rational. Six plus 13/3 is a rational number, and 6 minus 13/3 is also a rational number. If the solutions of a quadratic equation are rational, then the equation is factorable.

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WHat is 2x2x2x2x2x2+2=<br> 66<br> 76<br> 86<br> 96<br> 106
Alexeev081 [22]

Answer:

66

Step-by-step explanation:

2 \times 2 \times 2 \times 2 \times 2 \times 2+2= \\  \\  = 64 + 2 \\  \\  = 66

5 0
4 years ago
Find the arc length of the given curve between the specified points.
yuradex [85]

Answer:

4.25

Step-by-step explanation:

Given:

f(x) = \frac{x^3}{12} + \frac{1}{x} \\\\Arc Length = \int\limits^a_b {\sqrt{1 + (f'(x))^2}  } \, dx \\f '(x) = \frac{x^2}{6} - \frac{1}{x^2}\\\\f'(x)^2 = (\frac{x^2}{6} - \frac{1}{x^2})^2 = \frac{x^4}{36} +  \frac{1}{x^4} - \frac{1}{3}\\\\1 + f'(x)^2 = \frac{x^4}{36} +  \frac{1}{x^4} + \frac{2}{3}\\\\\= \frac{x^8 + 36 + 12x^4}{36x^4}\\\\= \frac{(x^4 + 6)^2}{36x^4}\\\\=\sqrt{1 + f'(x)^2}  = \sqrt{ \frac{(x^4 + 6)^2}{36x^4}}\\\\= \frac{x^2}{6} + \frac{1}{x^2} \\\\

ArcLength = \int\limits^4_1 {\frac{x^2}{6} + \frac{1}{x^2}  } \, dx \\= (\frac{x^3}{18} -  \frac{1}{x})\limits^4_1\\\\= (\frac{64}{18} - \frac{1}{4}) - (\frac{1}{18} - 1)\\\\= \frac{17}{4}= 4.25

8 0
3 years ago
How to solve part to whole?
BartSMP [9]

Divide I think divide them together
5 0
3 years ago
Read 2 more answers
Determine whether the sequence is arithmetic, geometric, or neither, and justify your response.
Kobotan [32]

9514 1404 393

Answer:

  geometric

Step-by-step explanation:

The signs of the terms alternate, so it cannot be an arithmetic sequence.

The ratios of terms are ...

  6/-3 = -12/6 = 24/-12 = -2

The terms have a constant ratio of -2, so the sequence is geometric.

6 0
3 years ago
Write an equation in slope intercept form given two points: (3,1),(0,10)
qaws [65]

Answer:

y = - 3x + 10

Step-by-step explanation:

We have to write an equation of a straight line in slope-intercept form that passes through the points (3,1) and (0,10).

Now, the equation of the straight line (using two points form) will be  

\frac{y - 1}{ 1 - 10} = \frac{x - 3}{3 - 0}

⇒ y - 1 = - 3(x - 3)

⇒ y - 1 = 9 - 3x

⇒ y = - 3x + 10 (Answer)

{Since the slope-intercept form of a straight line equation is y = mx + c}

We know the equation of a straight line when any two points on the straight line (x_{1},y_{1}),  (x_{2},y_{2}) are known, will be  

\frac{y - y_{1} }{y_{1} - y_{2}} = \frac{x - x_{1} }{x_{1} - x_{2}}

6 0
3 years ago
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