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3 years ago

Jen is 4/10 meters taller than her sister. Her sister is 9/10 meters tall. How tall is Jen?

Mathematics

1 answer:

mariarad [96]3 years ago

5 0

Add 4/10 to 9/10.

9/10 + 4/10 = 13/10

Simplify 13/10 into a mixed number by subtracting 10 from the numerator and turning it into a whole.

13/10 ⇒ 1 3/10

<h2>Answer:</h2>

Jen is 1 3/10 meters tall.

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A karat equals 1/24 part of gold in an alloy [ eg 9 karat gold is 9/24 gold]. How many grams of 9 karat gold must be mixed with

irinina [24]

This is a mixture problem.

Let the 9 karat gold to be mixed be x. The 18 karat would weight (200 - x). Since the total = 200g.

mass1 * karat1 + mass2*karat = total mass * total carat

Let mass1 be x g. mass 2 would be = (200 -x)
karat 1 = 9 karat 2 = 18

Total mass = 200g.
Total karat = 14.

9*x + 18*(200 -x) = 14*200

9x + 18*200 - 18*x = 14*200

18*200 + 9x - 18x = 14*200

3600 - 9x = 2800

3600 - 2800 = 9x

800 = 9x

9x = 800

x = 800/9

x ≈ 88.89

Therefore 88.89 grams of 9 karat gold must be mixed.

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2 years ago

Find the product of 3/5x15

VashaNatasha [74]

The answer for this is 9

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2 years ago

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There are 95 white pieces of paper in a hat along with 5 blue pieces of paper. What is the theoretical probability that a blind-

sp2606 [1]

Answer:

Step-by-step explanation:

Probability is the likelihood of an event taking place.

-Given there are 95 white and 5 blue pieces, the total number of papers is 100.

-The theoretical first attempt probability is equivalent to the number of each paper divided by the total:

$P(blue)= \frac{no \ of \ blue}{total}\\\\=\frac{5}{100}\\\\=0.05$

Hence, the theoretical probability that a blind-folded person draws a blue piece of paper on the first attempt is 0.05 or 5%

6 0

2 years ago

In 1943, an organization surveyed 1100 adults and asked, "Are you a total abstainer from, or do you on occasion consume, alc

Fynjy0 [20]

Answer:

We conclude that the proportion of adults who totally abstain from alcohol has changed.

Step-by-step explanation:

We are given that in 1943, an organization surveyed 1100 adults and asked, "Are you a total abstainer from, or do you on occasion consume, alcoholic beverages?"

Of the 1100 adults surveyed, 429 indicated that they were total abstainers. In a recent survey, the same question was asked of 1100 adults and 352 in

Let p = proportion of adults who totally abstain from alcohol.

where, p = $\frac{429}{1100}$ = 0.39

So, Null Hypothesis, $H_0$ : p = 39% {means that the proportion of adults who totally abstain from alcohol has not changed}

Alternate Hypothesis, $H_A$ : p $\neq$ 39% {means that the proportion of adults who totally abstain from alcohol has changed}

The test statistics that would be used here One-sample z proportion statistics;

T.S. = $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample proportion of adults who totally abstain from alcohol = $\frac{352}{1100}$ = 0.32

n = sample of adults surveyed = 1100

So, test statistics = $\frac{0.32-0.39}{\sqrt{\frac{0.32(1-0.32)}{1100} } }$

= -4.976

The value of z test statistics is -4.976.

Now, at 0.10 significance level the z table gives critical values of -1.645 and 1.645 for two-tailed test.

Since our test statistics doesn't lie within the range of critical values of z, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that the proportion of adults who totally abstain from alcohol has changed.

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2 years ago

A disk with radius 3 units is inscribed in a regular hexagon. Find the approximate area of the inscribed disk using the regular

Oksi-84 [34.3K]

Answer:

The approximate are of the inscribed disk using the regular hexagon is $A=18\sqrt{3}\ units^2$