3 years ago

Please help ASAP!!!!!!!!!!!

Mathematics

1 answer:

Sergeeva-Olga [200]3 years ago

4 0

Answer:

it's too blurryyyyyyyyyyyyyyyyyyyyy

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The answer is d okay

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3 years ago

If g (x) = 1/x then [g (x+h) - g (x)] /h

lys-0071 [83]

Answer:

$\dfrac{-1}{x(x+h)}, h\ne 0$

Step-by-step explanation:

If $g(x) = \dfrac{1}{x}$ , then $g(x+h) = \dfrac{1}{x+h}$ . It follows that

$\begin{aligned} \\\frac{g(x+h)-g(x)}{h} &= \frac{1}{h} \cdot [g(x+h) - g(x)] \\&= \frac{1}{h} \left( \frac{1}{x+h} - \frac{1}{x} \right)\end{aligned}$

Technically we are done, but some more simplification can be made. We can get a common denominator between 1/(x+h) and 1/x.

$\begin{aligned} \\\frac{g(x+h)-g(x)}{h} &= \frac{1}{h} \left( \frac{1}{x+h} - \frac{1}{x} \right)\\&=\frac{1}{h} \left(\frac{x}{x(x+h)} - \frac{x+h}{x(x+h)} \right) \\ &=\frac{1}{h} \left(\frac{x-(x+h)}{x(x+h)}\right) \\ &=\frac{1}{h} \left(\frac{x-x-h}{x(x+h)}\right) \\ &=\frac{1}{h} \left(\frac{-h}{x(x+h)}\right) \end{aligned}$

Now we can cancel the h in the numerator and denominator under the assumption that h is not 0.

$= \dfrac{-1}{x(x+h)}, h\ne 0$

5 0

3 years ago

ed has $36 to buy paint and brushes for school project. Jars of paint cost $4 each. The paint brushes are $2 each write an equat

Sauron [17]

Ok so basically it will be 4 x 3 = 12 which leaves $24 ok then you divide 24 by 2 and you get 12 so the amount of brushes that can be purchased is 12.

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3 years ago

What is the slope of the line with the points (3,5) and (6,4)

Bumek [7]

Answer:

The slope is -1/3

Step-by-step explanation:

(y2-y1)/(x2-x1)

(4-5)/(6-3)

-1/3

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(x + 3)2 + (y – 1)2 = 9

snow_tiger [21]

Answer:

do yr work lazey

Step-by-step expl

you will find this very intersting

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