Question

If a^{2}+bx^{2} =13 " align="absmiddle" class="latex-formula">, and ab=6, find the value of
a)$(a+b)^{2}$
b)$(a-b)^{2}$

Answer 1

$a^2-b^2=13;\ ab=6$

$a)\\(a+b)^2=a^2+2ab+b^2=(a^2+b^2)+2(ab)=13+2\cdot6=25\\\\b)\\(a-b)^2=a^2-2ab+b^2=(a^2+b^2)-2(ab)=13-2\cdot6=1$