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3 years ago

If

a^{2}+bx^{2} =13 " align="absmiddle" class="latex-formula">, and ab=6, find the value of
a) $(a+b)^{2}$
b) $(a-b)^{2}$

Mathematics

1 answer:

Mkey [24]3 years ago

7 0

$a^2-b^2=13;\ ab=6$

$a)\\(a+b)^2=a^2+2ab+b^2=(a^2+b^2)+2(ab)=13+2\cdot6=25\\\\b)\\(a-b)^2=a^2-2ab+b^2=(a^2+b^2)-2(ab)=13-2\cdot6=1$

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Read 2 more answers

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