6.05 x 10^5
I think this is the answer
Answer:
m∠AMO ≈ 54.7°
AΔANM = 486√3
Step-by-step explanation:
The edges are congruent, so all four faces are congruent equilateral triangles. We'll say the length of each edge is 2r.
The height of the pyramid h is given to be 36.
The perpendicular distance from O to line MP is called the apothem (a). Using 30-60-90 triangles, b = 2a and r = a√3.
Use cosine to find m∠AMO.
cos(∠AMO) = b / (2r)
cos(∠AMO) = (2a) / (2a√3)
cos(∠AMO) = 1 / √3
m∠AMO ≈ 54.7°
Use Pythagorean theorem to find the apothem.
(2r)² = b² + h²
(2a√3)² = (2a)² + 36²
12a² = 4a² + 1296
8a² = 1296
a² = 162
a = 9√2
So the edge length is:
2r = 2√3 (9√2)
2r = 18√6
The area of the equilateral triangle ΔANM is half the apothem times the perimeter:
A = ½aP
A = ½ (9√2) (3 × 18√6)
A = 243√12
A = 486√3
$9= k•8 euros so k=9/8=1.125
So for every 1 euro we have $1.125
y=1.125•x
$27=k•24 euros so k=28/24=1.166666667
y=1.67•x
Answer:
none
Step-by-step explanation:
If a squared variable is equal to a negative number, all of the solutions are imaginary
There are no real solutions
A and B lie on the line, yes, but what specifically are you supposed to do? Looks like your problem statement was cut off before you'd finished typing it in.
You say your line passes thru (-2,5) and has a slope of 2/3? Then, using the point-slope formula,
y-5 = (2/3)(x+2) This is the general equation for your line.
Now let's play around with B(-2,y). Suppose we subst. the x-coordinate of B, which is -2, into the equation y-5 = (2/3)(x+2); we get y-5 = (2/3)(-2+2) = 0. This tells us that y must be 5. But we already knew that!!
So, please review the original problems with its instructions and this discussion and tell me what you need to know from this point on.