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3 years ago

9

Which of the following polygons cannot be used to form a regular tessellation?A. Equilateral triangleB. Regular octagonC. Square

D. Regular hexagon

1 answer:

Nataly_w [17]3 years ago

5 0

A- Equilateral triangle.

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Determine the measures of the angles of MNO if the measures of the angles are in the ratio 2:4:6

saul85 [17]

2:4:6 =2x :4x :6x
2x -1st angle
4x -2d one
6x - 3d one
2x+4x+6x=180 because MNO is a triangle
12x=180
x=180/12=15

2*15=30° -1st angle
4*15= 60° -2d one
6*15=90° - 3d one

4 0

3 years ago

I'm stuck on this question, any ideas? thanks

True [87]

Answer:

$\lim_{x \to 0} \frac{\frac{1}{6+x}-\frac{1}{6}}{x}=-1/36$

Step-by-step explanation:

So we have the limit:

$\lim_{x \to 0} \frac{\frac{1}{6+x}-\frac{1}{6}}{x}$

Let's remove the fractions in the denominator by multiplying both layers by (6+x)(6). So:

$\lim_{x \to 0} \frac{\frac{1}{6+x}-\frac{1}{6}}{x}\cdot (\frac{(6+x)(6)}{(6+x)(6)})$

Distribute:

$=\lim_{x \to 0} \frac{(6)-(6+x)}{x(6+x)(6)}$

Simplify the numerator:

$=\lim_{x \to 0} \frac{6-6-x}{x(6+x)(6)}\\=\lim_{x \to 0} \frac{-x}{x(6+x)(6)}$

Both the numerator and the denominator have an x. Cancel:

$=\lim_{x \to 0} \frac{-1}{(6+x)(6)}$

Direct substitution:

$= \frac{-1}{(6+0)(6)}$

Simplify:

$=-1/36$

And that's our answer.

And we're done!

8 0

3 years ago

Read 2 more answers

What is the k’s meaning in k over 5 = 5

ELEN [110]

Answer:

25

Step-by-step explanation

5 times 5 is 25

(To make problems like this easier just multiply the denominator by the result, take this problem for example, the denominator is 5 and the result is 5 so just multiply those and you get 25)

4 0

3 years ago

Help me please ASAP

brilliants [131]

ans is c it is simple c only meet the need of questions

4 0

3 years ago

Am I right or wrong?

omeli [17]

You are absolutely right.

8 0

3 years ago