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2 years ago

What is the k’s meaning in k over 5 = 5

Mathematics

1 answer:

ELEN [110]2 years ago

4 0

Answer:

Step-by-step explanation

5 times 5 is 25

(To make problems like this easier just multiply the denominator by the result, take this problem for example, the denominator is 5 and the result is 5 so just multiply those and you get 25)

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Vito uses 9 L of water to water 24 flowerpots he is wondering how many liters of water it would take to water 40 flowerpots

Elenna [48]

Using ratios, 9 : 24
Find ? : 40

Solving Steps-
40 / 24 = 1 2/3

1 2/3 • 9 = 15

ANSWER is 15 L

8 0

3 years ago

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Sharon can buy cards in boxes of 12 and stamps in packages of 20 what is the least number of boxes of cards she should buy?

-Dominant- [34]

The least number of boxes Sharon should buy is 5 boxes.

Step-by-step explanation:

Given,

Number of cards in box = 12

Number of stamps in packages = 20

We will find least common multiple of 12 and 20.

12 = 12,24,36,48,60,.....

20 = 20,40,60,80,....

The LCM of 12 and 20 is 60.

Now,

12 cards = 1 box

60 cards = $\frac{60}{12}\ boxes$

60 cards = 5 boxes

The least number of boxes Sharon should buy is 5 boxes.

8 0

3 years ago

Use induction to prove: For every integer n > 1, the number n5 - n is a multiple of 5.

nignag [31]

Answer:

we need to prove : for every integer n>1, the number $n^{5}-n$ is a multiple of 5.

1) check divisibility for n=1, $f(1)=(1)^{5}-1=0$ (divisible)

2) Assume that $f(k)$ is divisible by 5, $f(k)=(k)^{5}-k$

3) Induction,

$f(k+1)=(k+1)^{5}-(k+1)$

$=(k^{5}+5k^{4}+10k^{3}+10k^{2}+5k+1)-k-1$

$=k^{5}+5k^{4}+10k^{3}+10k^{2}+4k$

Now, $f(k+1)-f(k)$

$f(k+1)-f(k)=k^{5}+5k^{4}+10k^{3}+10k^{2}+4k-(k^{5}-k)$

$f(k+1)-f(k)=k^{5}+5k^{4}+10k^{3}+10k^{2}+4k-k^{5}+k$

$f(k+1)-f(k)=5k^{4}+10k^{3}+10k^{2}+5k$

Take out the common factor,

$f(k+1)-f(k)=5(k^{4}+2k^{3}+2k^{2}+k)$ (divisible by 5)

add both the sides by f(k)

$f(k+1)=f(k)+5(k^{4}+2k^{3}+2k^{2}+k)$

We have proved that difference between $f(k+1)$ and $f(k)$ is divisible by 5.

so, our assumption in step 2 is correct.

Since $f(k)$ is divisible by 5, then $f(k+1)$ must be divisible by 5 since we are taking the sum of 2 terms that are divisible by 5.

Therefore, for every integer n>1, the number $n^{5}-n$ is a multiple of 5.

3 0

3 years ago

FASTTT HURRYYYY PLEASEEEEEE<br> The pair of figures is similar. Find the missing side.

Vladimir [108]

The answer is x=12 :)

6 0

3 years ago

It is not A. or B. I will give brainliest

mars1129 [50]

Answer:

2m + 4 = 5

Step-by-step explanation:

Cross multiply.

2(m + 2) = 5 * 1

2m + 4 = 5

Answer: 2m + 4 = 5

3 0

2 years ago

Read 2 more answers