All categories

3 years ago

What's the fraction of 3.5

Mathematics

2 answers:

lys-0071 [83]3 years ago

5 0

7/2 is your answer good luck with your homework

jonny [76]3 years ago

4 0

A fraction is simply a simpler way of putting a decimal, as it represents the division. Example, when something is half, or .5, it can be described as one divided by two, or 1/2

Since 3.5 is three, and a half, sum the two of them and you get 3 1/2, or, multiply 3 by 2 and get 6, and add that to 1 to get seven
You will get 7/2

You might be interested in

Fill in the blank please

Anastaziya [24]

Answer:

240

Step-by-step explanation:

you do 3x10 which is 30 then multiply that by 8 and you have your answer.

5 0

3 years ago

HELP ME!!!!!!!!!The potatoes beth brought weighed 3 kilograms and 420 grams. Her onions weighed 1,050 grams less than the potato

Volgvan

I think 306? Not completely sure! Hope this helps!!

5 0

3 years ago

Kira made 4 identical necklaces, each having beads and a pendant. The total cost of the beads and pendants for all 4 necklaces w

snow_lady [41]

Answer: 2.10

Step-by-step explanation: 2.10 * 4 + 6

7 0

3 years ago

Michael is planting a garden. The probability that a seed will produce a plant is 9/10

Lapatulllka [165]

The probability that the seed will produce a plant is almost certain at 90%

6 0

3 years ago

Find the value of the variable y, where the sum of the fraction 2/y-3 and 6/y+3 is equal to the quotient.

NISA [10]

Answer:

Here we need to solve:

$\frac{2}{y - 3} + \frac{6}{y + 3 } = \frac{\frac{2}{y-3}}{\frac{6}{y + 3} }$

The sum of the fractions is equal to the quotient between the fractions.

Notice that the two values:

y = 3

y = -3

make the denominator equal to zero, so those values are restricted.

We can simplify the right side to get:

$\frac{2}{y - 3} + \frac{6}{y + 3 } = \frac{\frac{2}{y-3}}{\frac{6}{y + 3} } = \frac{2*(y + 3)}{6*(y - 3)} = 3*\frac{y + 3}{y - 3}$

Now we can multiply both sides by (y - 3)

$(y - 3)*(\frac{2}{y - 3} + \frac{6}{y + 3 }) = 3*(y + 3)\\2 + 6*\frac{y -3}{y + 3} = 3*(y + 3)$

Now we can multiply both sides by (y + 3)

$(2 + 6*\frac{y -3}{y + 3})*(y + 3) = 3*(y + 3)*(y + 3)$

$2*(y + 3) + 6*(y - 3) = 3*(y + 3)*(y + 3)\\\\2*y + 6 + 6*y - 18 = 3*(y^2 + 2*y*3 + 9)\\\\8*y - 12 = 3*y^2 + 6*y + 33\\\\0 = 3*y^2 + 6*y + 33 - 8*y + 12\\\\0 = 3*y^2 - 2*y + 45$

First, let's see the determinant of that quadratic equation:

$D = (-2)^2 - 4*3*45 = -536$

We can see that it is negative, thus, there are no real solutions of the equation.

Thus, there is no value of y such that the origina equation is true,

6 0

3 years ago