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asambeis [7]
3 years ago
10

Factor:

Mathematics
1 answer:
liubo4ka [24]3 years ago
6 0
The answer is D. (4x-5)(4x+5)
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The ratio to hearts to moons is | The ratio of moons to all shapes is. I need help due in 10 minutes
Alinara [238K]

Hearts to moon= 6:4

                         = 3:2 (simplified)

Moon to all shapes= 4:10

                               = 2:5 (simplified)

4 0
3 years ago
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You pay $30 each month for satellite TV, plus $2.50 for every movie you purchase. Write and solve an equation to find the number
raketka [301]
The initial payment per month being 30 and each movie being 2.50 means that if the total payment is 45 then you pay for 6 movies per month, 30x+6(2.5x)
7 0
3 years ago
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Count the left handed and right handed spirals on the cacti in the photograph you should get two consecutive terms of the Fibona
lana [24]
You can count the spirals because they are coloured.

The left handed spirals are in red and you can count 13.

The rifht hanged spirals are in yellow and you can count 21.

Fibonacci sequence is: 1, 1, 2, 3, 5, 8, 13, 21, 34, 55, 89, ... From 2 the next number is the sum of the two previous numbers:

2 = 1 + 1

3 = 2 + 1

5 = 3 + 2

8 = 5 + 3

13 = 8 + 5

21 = 13 + 8.

Fibonacci numbers are found in many structures in nature.

We have just found that these cacti enclose Fibonacci numbers 13 and 21.

Answer: 13 and 21
8 0
4 years ago
What is the coefficient b makes the equation true for any real number x -3 (2x-3) + 5x = bx + 9
QveST [7]

Answer:

b = 0

Step-by-step explanation:

x -3 (2x-3) + 5x = bx + 9

x - 6x +9 + 5x = bx + 9

-9 -9

x - 6x + 5x = bx

-5x + 5x = bx

0 = bx

b/x 0/x

b = 0

3 0
3 years ago
The manager of a music store has kept records of
Marysya12 [62]

Answer:

(a) P(x\le 3) = 0.75

(b) P(x\le 3) = 0.75

<em>(b) is the same as (a)</em>

(c) P(x \ge 5) = 0.10

(d) P(x = 1\ or\ 2) = 0.55

(e) P(x > 2) = 0.45

Step-by-step explanation:

Given

\begin{array}{ccccccc}{CDs} & {1} & {2} & {3} & {4} & {5} & {6\ or\ more}\ \\ {Prob} & {0.30} & {0.25} & {0.20} & {0.15} & {0.05} & {0.05}\ \ \end{array}

Solving (a): Probability of 3 or fewer CDs

Here, we consider:

\begin{array}{cccc}{CDs} & {1} & {2} & {3} \ \\ {Prob} & {0.30} & {0.25} & {0.20} \ \ \end{array}

This probability is calculated as:

P(x\le 3) = P(1) + P(2) + P(3)

This gives:

P(x\le 3) = 0.30 + 0.25 + 0.20

P(x\le 3) = 0.75

Solving (b): Probability of at most 3 CDs

Here, we consider:

\begin{array}{cccc}{CDs} & {1} & {2} & {3} \ \\ {Prob} & {0.30} & {0.25} & {0.20} \ \ \end{array}

This probability is calculated as:

P(x\le 3) = P(1) + P(2) + P(3)

This gives:

P(x\le 3) = 0.30 + 0.25 + 0.20

P(x\le 3) = 0.75

<em>(b) is the same as (a)</em>

<em />

Solving (c): Probability of 5 or more CDs

Here, we consider:

\begin{array}{ccc}{CDs} & {5} & {6\ or\ more}\ \\ {Prob} & {0.05} & {0.05}\ \ \end{array}

This probability is calculated as:

P(x \ge 5) = P(5) + P(6\ or\ more)

This gives:

P(x\ge 5) = 0.05 + 0.05

P(x \ge 5) = 0.10

Solving (d): Probability of 1 or 2 CDs

Here, we consider:

\begin{array}{ccc}{CDs} & {1} & {2} \ \\ {Prob} & {0.30} & {0.25} \ \ \end{array}

This probability is calculated as:

P(x = 1\ or\ 2) = P(1) + P(2)

This gives:

P(x = 1\ or\ 2) = 0.30 + 0.25

P(x = 1\ or\ 2) = 0.55

Solving (e): Probability of more than 2 CDs

Here, we consider:

\begin{array}{ccccc}{CDs} & {3} & {4} & {5} & {6\ or\ more}\ \\ {Prob} & {0.20} & {0.15} & {0.05} & {0.05}\ \ \end{array}

This probability is calculated as:

P(x > 2) = P(3) + P(4) + P(5) + P(6\ or\ more)

This gives:

P(x > 2) = 0.20+ 0.15 + 0.05 + 0.05

P(x > 2) = 0.45

3 0
3 years ago
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