Question:
Jesse and Amir were assigned the same book to read. Jesse started reading on Saturday, and he is reading 30 pages a day. Amir didn't start until Sunday, but he is reading 35 pages a day.
How many days will it take Amir to catch up to Jesse, and how many pages will they each have read?
Write an equation to represent the number of pages Amir has read. Use x to represent the number of days Amir has been reading and y to represent the number of pages he has read.
Answer:
It will take 6 days
Step-by-step explanation:
For Jesse:

This implies that Jesse will cover 30y in y days
For Amir:

This implies that Amir will cover 35x in x days
Because Amir starts a day later,

So, we have the following equations:



To get the number of days when they read the same number of pages, we have:

Substitute values for Jesse and Amir

Substitute x + 1 for y

Open bracket

Collect Like Terms


Solve for x




Hello!
First of all let's find the perimeter (circumference) of the semi circles. We can combine them to make one circle with a diameter of 4 (as we can see the side length of one semi circle is 4 cm. We now plug it into the circumference equation (

=3.14).
4(3.14)=12.56
Now we add up the side lengths of the rectangle.
4+6+4+6=20
Now we add up the length of our circle and rectangle.
20+12.56=32.56
Therefore our answer is
32.56 cm.
----------------------------------------------------------
Now to find the area! If we combine the two semicircles, we get a circle with a diameter of four. This means that is has a radius of two. We use the equation below to find the area of the two circles.
A=

r²
First we will square our radius.
2(2)=4
Now we multiply by pi.
4(3.14)=12.56
Now we need to find the area of the rectangle.
6(4)=24
Now we add.
24+12.56=
36.56.
I hope this helps!
Answer:
2
Step-by-step explanation:
Answer:
Step-by-step explanation:
If the square has an area of 49 ft^2, then the length of one of its sides is
s = √(49 ft^2) = 7 ft, and its perimeter is P = 4(7 ft) = 28 ft.
As for the rectangle: let W and L represent the width and length, respectively. Then W*L = 24 ft^2 is the area. L = W + 2 ft. Therefore,
W(W + 2) = 24, or W^2 + 2W - 24 = 0, or (W +6)(W - 4) = 0. Thus, W = 4 ft.
The perimeter of this rectangle is P = 2W + 2L, or
P = 2(4 ft) + 2(6 ft) = 24 ft.
The square has the larger perimeter: It is 28 ft.