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MrRissso [65]
3 years ago
11

Hi! can someone answer this math problem? its x-7y=-11 ; 5x+2y=-18,,, if so can anyone do it step by step? please and thank you!

!
ps: when u answer it pls use either the substitution method or elimination method, either way works:),
Mathematics
1 answer:
Stella [2.4K]3 years ago
8 0

Answer:

X = -4  and Y = 1 (sorry if wrong im only in 6th grade ;(

Step-by-step explanation:

X - 7Y = -11 ......(i)

5X + 2Y = -18 ........(ii)

multiply equation (i) by 5 we get 5X - 35Y = -55 ....(iii)

subtract equation (ii) from (iii)

we get -37Y = -37 ⇒ Y = 1

now put the value of Y from above in equation (i)

we get X = -4

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3.(08.07 HC)
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Answer:

For a general equation:

y = f(x) =  a*x^2 + b*x + c

The x-intercepts are given by:

x = \frac{-b \pm \sqrt{b^2 - 4*a*c} }{2*a}

And the vertex is the point (h, k) such that:

h = -b/2*a

k = f(h)

Part A)

We have the function f(x) = -16*x^2 + 22*x + 3

The x-intercepts are then:

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The two intercepts are:

x = (-22 - 26)/(-32) = 1.5

x = (-22 + 26)/(-32) = -0.125

Part B:

The vertex is (h, k), such that:

h = -22/(2*(-16)) = -22/-32 = 0.6875

k = f(0.6875) = -16*(0.6875)^2 + 22*0.6875 + 3 = 10.6525

Then the vertex is: ( 0.6875, 10.6525)

If the leading coefficient is positive, then the vertex is a minimum

If the leading coefficient is negative, then the vertex is a maximum.

In this case the leading coefficient is -16, then we can conclude that the vertex is a maximum.

Part C:

To graph the function, we can graph the points that we already know (the vertex and the two x-intercepts) and connect them with a curve.

You could also add another few points so you have a guide to draw the curve, for example the point:

y = f(0) = -16*0^2 + 22*0 + 3

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(0, 3)

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