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mina [271]
3 years ago
10

What is the volume of silver metal which weighs 820.0g.the density of silver is 10.5g/cm3.

Mathematics
1 answer:
Anestetic [448]3 years ago
4 0
Volume of Silver  =  \frac{MASS}{DENSITY}
                      
                            =  \frac{820.0  g}{10.5  g / cm ^{3} }
 
                            =  78.095 cm³
 
                            ≈  78.10 cm³



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Katena32 [7]

Answer: 2.5 ounces/ pint

You can firstly turn your fractions into decimals 5/8 is equal to .625 and 1/4 is .25

Then you can divide .625 by .25 which is 2.5, So the unit rate is 2.5 ounces per pint.

4 0
3 years ago
AWARDING EXTRA POINTSWhat is the distance between point A (-3, -2) and Point B (4, -7)?
kenny6666 [7]

Answer:

Hi there!

Your answer is:

<em>8</em><em>.</em><em>6</em><em> </em><em>units</em>

Step-by-step explanation:

The distance formula is

√ ( (x2-x1)^2 + (y2-y1)^2 )

In your points:

A (-3, -2)

-3 is x1

-2 is y1

B (4, -7)

4 is x2

-7 is y2

Plug in to distance formula

√ ( 4-( -3))^2 + ( -7 - (-2))^2

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This equals roughly 8.6 units!

4 0
3 years ago
What is the LCM and GCF of<br> 37 and 12
RSB [31]
I hope this helps you

7 0
3 years ago
Consider the functions below. f(x, y, z) = x i − z j + y k r(t) = 4t i + 6t j − t2 k (a) evaluate the line integral c f · dr, wh
fredd [130]

With

\vec r(t)=4t\,\vec\imath+6t\,\vec\jmath-t^2\,\vec k

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The vector field evaluated over this parameterization is

\vec f(x,y,z)=\vec f(x(t),y(t),z(t))=4t\,\vec\imath+t^2\,\vec\jmath+6t\,\vec k

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\displaystyle\int_{-1}^1(4t\,\vec\imath+t^2\,\vec\jmath+6t\,\vec k)\cdot(4\,\vec\imath+6\,\vec\jmath-2t\,\vec k)\,\mathrm dt

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6 0
3 years ago
Y
Anuta_ua [19.1K]
It’s should be the second on so b and you should get it corrdct
7 0
3 years ago
Read 2 more answers
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