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Cerrena [4.2K]
1 year ago
5

A sequence is defined recursively using the formula f(n 1) = f(n) – 5 . which sequence could be generated using this formula? 1,

–5, 25, –125, ... 2, 10, 50, 250, ... 3, –2, –7, –12, ... 4, 9, 14, 19, ...
Mathematics
1 answer:
frozen [14]1 year ago
6 0

Since the sequence has a common difference of 5, hence the sequence  is 4, 9, 14, 19, ... is defined recursively using the formula  f(n 1) = f(n) – 5 .

<h3>Recursive functions</h3>

Recursive functions are functions used to generalize sequence. Given the recursive function

f(n - 1) = f(n) – 5 .

This can be written as:

f(n) - f(n-1) = 5

This shows that the correct sequence must have a common difference of 5

For the sequence 4, 9, 14,19...

d = 9 - 4 = 14 - 9

d = 5

Since the sequence has a common difference of 5, hence the sequence  is 4, 9, 14, 19, ... is defined recursively using the formula  f(n 1) = f(n) – 5

Learn more on recursive functions here: brainly.com/question/489759

#SPJ4

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Given that

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Let f(x)= 100 / −10+ e^ −0.1x . What is f(−6) ?
bija089 [108]

The value of f(-6) is -12.2

Explanation:

Given that the function f(x)=\frac{100}{-10+e^{-0.1\left(x\right)}}

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The value of f(-6) can be determined by substituting the value for x=-6 in the function and simplify the function.

Hence, let us substitute x=-6 in the function, we get,

f(-6)=\frac{100}{-10+e^{-0.1\left(-6\right)}}

Let us apply the rule -\left(-a\right)=a , we get,

f(-6)=\frac{100}{-10+e^{0.1\left(6\right)}}

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f(-6)=\frac{100}{-10+e^{0.6}}

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f(-6)=-12.2

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