Answer: D
Within a specific time period or by a specific user
Explanation:
Answer:
following are the OSI Layers
1.physical layer
2.datalink layer
3.network layer
4.transport layer
5.session layer
6.presentation layer
7.application layer
Explanation:
physical layer is used to transmit media,signal and binary information
datalink layer is used for physical addressing MAC and LLC
network layer is used for path determination and ip
transport layer is for end to end communication and reliability
session layer is for interhost communication
presentation layer is for data representation and encryption
application layer is network process to application
Answer:
"Router screening" is the correct option.
Explanation:
- A router that philters packets like a firewall. For certain instances, the whole firewall system is such a single scanning router.
- Often connected to a network stage as well as a container-filter firewall has been the scanning router firewall. This rather firewall operates by filtering protocol characteristics from received packets.
So that the above seems to be the correct approach.
Answer:
#include <string>
#include <iostream>
using namespace std;
int main() {
string userInput;
getline(cin, userInput);
// Here, an integer variable is declared to find that the user entered string consist of word darn or not
int isPresent = userInput.find("darn");
if (isPresent > 0){
cout << "Censored" << endl;
// Solution starts here
else
{
cout << userInput << endl;
}
// End of solution
return 0;
}
// End of Program
The proposed solution added an else statement to the code
This will enable the program to print the userInput if userInput doesn't contain the word darn
mbly code to implement the y=(x1+x2)*(x3+x4) expression on 2-address machine, and then display the value of y on the screen. Assume that the values of the variables are known. Hence, do not worry about their values in your code.
The assembly instructions that are available in this machine are the following:
Load b, a Load the value of a to b
Add b, a Add the value of a to the value of b and pla