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3 years ago

Given the equation 5x + 23 = − 2x − 12, which order of operations completely solves for x? (1 point)

Mathematics

1 answer:

Brrunno [24]3 years ago

5 0

5x+23+-2x-12
7x+23=-12
7x=-35
x=5

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Solve sint = cos2t, for –4π ≤ t ≤ –2π

e-lub [12.9K]

Answer:

-(23/6)π

-(19/6)π

-3π

Step-by-step explanation:

cos2t=cos^2t-sin^2t => cos^2t=1-sin^2t =>cos2t=1-2sin^2t

sint=1-2sin^2t, if x=sint, thenn we have 2x^2+x-1=0

Here x=0.5, x=-1, as x=sint => sint = -1 solutions for -4π to -2π is t=-3π,

sint = 0.5 solutions for -4π to -2π is t= -(23/6)*π, and t = -(19/6)*π

3 0

3 years ago

An artist is painting a flower pot that each require 1/34 gallons of paint what is the maximum numbers of flowerpots the artist

lara [203]

Answer:

Step-by-step explanation:

Hello There!

We can easily calculate the amount of flower pots he can paint by dividing the amount of paint he has by how much paint each flower pot requires

$\frac{.75}{\frac{1}{34} } =25.5$

The closest number is 24 therefore your answer is C

8 0

3 years ago

PLEASE HELP.... The Question is .. Which equation best represents the graph shown below. Explain in detail how you arrived at yo

atroni [7]

The answer is D. y = 1/2(x+2)^2 -3

Step-by-step explanation:

I just put each answer choice into a graphing calculator and chose the one that was equivalent, D. came out to be right

8 0

3 years ago

To prove :One plus cot square theta into tan theta by sec square theta = cot theta

pickupchik [31]

we are given

$\frac{(1+cot^2(\theta))*tan(\theta)}{sec^2(\theta)} =cot(\theta)$

We will simplify left side and make it equal to right side

Left side:

$\frac{(1+cot^2(\theta))*tan(\theta)}{sec^2(\theta)}$

we can use trigonometric identity

$1+cot^2(\theta)=csc^2(\theta)$

we can replace it

$\frac{(csc^2(\theta))*tan(\theta)}{sec^2(\theta)}$

we know that

csc=1/sin and sec=1/cos

so, we can replace it

and we get

$\frac{cos^2(\theta)tan(\theta)}{sin^2(\theta)}$

now, we know that

tan =sin/cos

$\frac{cos^2(\theta)*sin(\theta)}{sin^2(\theta)*cos(\theta)}$

we can simplify it

and we get

$\frac{cos(\theta)}{sin(\theta)}$

we can also write it as

$=cot(\theta)$

Right Side:

$cot(\theta)$

we can see that

left side = right side

so,

$\frac{(1+cot^2(\theta))*tan(\theta)}{sec^2(\theta)} =cot(\theta)$ ......Answer

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3 years ago

Graph the line slope 5 and y-intersept -3

notsponge [240]

Y=mx+b
m=slope
b=yint

given
slope=5=m
yint=-3=b
y=5x-3

3 0

3 years ago