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Oksi-84 [34.3K]
3 years ago
10

433x3 how u start this off

Mathematics
2 answers:
Aneli [31]3 years ago
5 0

Answer:

1299

Step-by-step explanation:

Okay to start off with you are going to look at this problem simply as individual numbers:

400, 30 , 3

And then you multiply 400 by 3, 30 by 3 and 3 by 3

400 * 3 = 1200

30 * 3 = 90

3 * 3 = 9

Now you place them in their respective places:

1200 + 90 + 9 = 1299

Hence you have your answer

Hope this helps you.

den301095 [7]3 years ago
4 0
Answer :
433 x 3
1299
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Last year there were 120 students in choir. This year, 30% more students took choir. How many students are taking choir this yea
soldi70 [24.7K]

Answer:

156 students

Step-by-step explanation:

To find how many students are in choir this year, multiply 120 by 1.3

120(1.3)

= 156

So, this year, 156 students are taking choir

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3 years ago
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What is the value of an annuity due at the end of 15 years of quarterly deposits of $2,000.00 with terms of 8 percent compounded
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3 years ago
A. The point-slope form of the equation of a line is y ? y1 = m(x ? x1), where m is the slope and (x1, y1) is a point on the lin
Rudiy27

Answer:

A.

y - 5 = -2(x-6)

Negative reciprocal gives you the perpendicular slope so negative reciprocal of 1/2 is -2.

Then apply point-slope form.

B. The answer is x = 6.

The midpoint of JK is

\left( \frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2} \right) = \left( \frac{8+ 4}{2}, \frac{4 + 4}{2} \right) = \left(6,4\right)

The line that goes through JK is just a horizontal line y = 4 because the y-coordinate does not change. So its perpendicular bisector is the vertical line that goes through the x-coordinate of the midpoint, that is, x = 6.

8 0
2 years ago
Please help i put a picture below
PSYCHO15rus [73]

Answer:

Step-by-step explanation:

This is not nearly as threatening and scary as I first thought it was.  You must be in the section in Geometry where you are taught that perimeter of similar figures exist in a one-to-one relationship while areas of similar figures exist in a squared-to-squared relationship.  We will use that here.  

The area formula for a regular polygon is

A=\frac{1}{2}ap where a is the apothem and p is the perimeter.  We are first asked for the area of the polygon, but it would make more sense to find the perimeter first, since we need it to find the area.

P = 5(8) so

P = 40

We are given that the area of the triangle inside that polygon is 22.022 units squared.  Knowing that the area formula for a triangle is

A=\frac{1}{2}bh we can sub in what we know and solve to find the height:

22.022=\frac{1}{2}(8)h and

22.022 = 4h so

h = 5.5055 units

It just so happens that the height of that triangle is also the apothem of the polygon, so now we have what we need to find the area of the polygon:

A=\frac{1}{2}(5.5055)(40)

which gives us an area of

A = 110.11 units squared.

Here is where we can use what we know about similar figures and the relationships between perimeters and areas.  We will set up a proportion with the smaller polygon info on top and the larger info on bottom.  We know that the larger is 3 times the smaller, so the ratio of smaller to larger is

\frac{s}{l}:\frac{1}{3}

Since perimeter is one-to-one and we know the perimeter of the smaller, we can create a proportion to solve for the perimeter of the larger:

\frac{s}{l}:\frac{1}{3}=\frac{40}{x}

Cross multiply to get that the perimeter is 120 units.  You could also have done this by knowing that if the larger is 3 times the size of the smaller, then the side measure of the larger is 24, and 24 * 5 = 120.  But we used the way we used because now we have a means to find the area of the larger since we know the area of the smaller.

Area exists in a squared-to-squared relationship of the perimeter which is one-to-one.  If the perimeter ratio is 1:3, then the area relationship is

\frac{s}{l}:\frac{1^2}{3^2} which is, simplified:

\frac{s}{l}:\frac{1}{9}

Since we know the area for the smaller, we can sub it into a proportion and cross multiply to solve for the area of the larger.

\frac{s}{l} :\frac{1}{9} =\frac{110.11}{x}

A of the larger is 990.99 units squared

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3 years ago
John has a map that shows a rectangular park with a circular pond. The scale on the map is 114 cm : 8 yd. On the map, the width
Ivenika [448]

Answer:

The area of the park is 119,966.14 cm if needed to round it would be 119,966 cm.

Step-by-step explanation:

first we would use A=length x width

so a = 614 cm x 212 cm = 130,168 cm

now we find the area of the pond using a= pi x r^2

the diameter is 114 cm so we cut that in half to find the radius which is 57 cm

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now we subtract the area of the pond from the whole area

130,168 - 10201.86 = 119,966.14 cm

The area of the park is 119,966.14 cm if needed to round it would be 119,966 cm

4 0
2 years ago
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