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Anestetic [448]
3 years ago
5

What is the output of the following program?

Computers and Technology
1 answer:
Contact [7]3 years ago
3 0

The question is poorly formatted:

<em>#include <stdio.h> </em>

<em>int main() { </em>

<em>int arr [5] = {1, 2, 3, 4, 5}; </em>

<em>arr [1] = 0; </em>

<em>arr [3] = 0; </em>

<em>for (int i = 0;i < 5; i+=1) </em>

<em>printf("%d", arr[i]); </em>

<em>return 0; </em>

<em>}</em>

Answer:

The output is 10305

Explanation:

I'll start my explanation from the third line

This line declares and initializes integer array arr of 5 integer values

<em>int arr [5] = {1, 2, 3, 4, 5}; </em>

<em />

This line sets the value of arr[1] to 0

<em>arr [1] = 0; </em>

<em>At this point, the content of the array becomes arr [5] = {1, 0, 3, 4, 5};</em>

This line sets the value of arr[3] to 0

<em>arr [3] = 0; </em>

<em>At this point, the content of the array becomes arr [5] = {1, 0, 3, 0, 5};</em>

<em />

The next two lines is an iteration;

The first line of the iteration iterates the value of i order from 0 to 4

<em>for (int i = 0;i < 5; i+=1) </em>

<em />

This line prints all elements of array arr from arr[0] to arr[4]

<em>printf("%d", arr[i]); </em>

<em />

<em>So, the output will be 10305</em>

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Following are the answer to this question:

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Explanation:

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