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True [87]
3 years ago
7

A cone has a radius of 4 units and a height of 6 units.

Mathematics
2 answers:
zubka84 [21]3 years ago
7 0

Answer:

Volume of the cone: 32π cubed unit

Step-by-step explanation:

Volume of cone: V=1/3hπr²

1/3 x 6 x π x 4^2 = 32π

elena55 [62]3 years ago
6 0

Answer:

The volume of a cone is 100.53. If you want to round it to the nearest one. It's 101.

Step-by-step explanation:

To find the volume. Use the equation V=3.14r^2 h/3

r=4 and h=6 so the equation is V=3.14(4^2) 6/3

V=50.24(6) = 100.53

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Bicycle rentals cost $5.00 per hour for an adult and $2.50 per hour for a child.
monitta

Answer:

B

Step-by-step explanation:

Have a good day!

3 0
3 years ago
A triangle has side lengths of 5 inches, 12 inches, and 15 inches. Every dimension is multiplied by 1/5 to form a new triangle.
Butoxors [25]

a = 5 in

b = 12 in

c = 15 in

the lengths of the sides a, b and c

the perimeter is P = a + b + c = 5 + 12 + 15 = 32 in

let the dimensions of the new triangle be

a1 = (1/5)*5 in

b1 = (1/5)*12 in

c1 = (1/5)*15 in

the perimeter is P1 = a1 + b1 + c1 = (1/5)5 + (1/5)12 + (1/5)15 = (1/5)(5 + 12 + 15) = (1/5)P1

P1 = (1/5)P

P1/P = 1/5 = a/a1 = b/b1 = c/c1

the ratio of the perimeters is equal to the ratio of the corresponding sides.

3 0
2 years ago
5. Elijah eats of a grapefruit every morning for breakfast. Which fraction shows how many grapefruits he will eat in 7 days? SOM
dezoksy [38]

Answer:

7/2

Step-by-step explanation:

he will have eaten 3.5 grapefruits in 7 days

7/2= 3.5

3 0
2 years ago
Write the limit as a definite integral on the interval [a, b], where ci is any point in the ith subinterval. Limit Interval lim
geniusboy [140]

Answer:

The corresponding definite integral may be written as

\int_a^b \mathrm{(4x + 11)}\,\mathrm{d}x

The answer of the above definite integral is

\int_a^b \mathrm{(4x + 11)}\,\mathrm{d}x = 98

Step-by-step explanation:

The given limit interval is

\lim_{||\Delta|| \to 0}  \sum\limits_{i=1}^n (4c_i + 11) \Delta x_i

[a, b] =  [-8, 6]

The corresponding definite integral may be written as

\int_a^b \mathrm{(4x + 11)}\,\mathrm{d}x

\int_{-8}^6 \mathrm{(4x + 11)}\,\mathrm{d}x

Bonus:

The definite integral may be solved as

\int_{-8}^6 \mathrm{(4x + 11)}\,\mathrm{d}x \\\\\frac{4x^2}{2} + 11x \left \|{b=6} \atop {a=-8}} \right. \\\\2x^2 + 11x \left \|{b=6} \atop {a=-8}} \right. \\\\ 2(6^2 -(-8)^2 ) + 11(6 - (-8) \\\\2(36 - 64 ) + 11(6 + 8) \\\\2(-28 ) + 11(14) \\\\-56 +154 \\\\98

Therefore, the answer to the integral is

\int_a^b \mathrm{(4x + 11)}\,\mathrm{d}x  = 98

5 0
3 years ago
The measure of two angles are (3x+20) and (5x - 2). What is the value of x if the
adelina 88 [10]

Answer:

x = 9

Step-by-step explanation:

angle 1 plus angle 2 equals 90 because they are complementary. combining like terms gives you 8x + 18 = 90. then you get 8x = 72, which means that x equals 9

8 0
3 years ago
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