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Fittoniya [83]
3 years ago
11

21x+3y=18 in point slope from

Mathematics
1 answer:
sveta [45]3 years ago
3 0

Answer:

y=-7x+6

Step-by-step explanation:

-21 divided by 3x is- 7x . 18 divided by 3 is 6.

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21. Choose the correct solution and graph for the inequality. (1 point)
Ilya [14]
Solve for X on both equations

2x - 2 < -12

Add two on both sides
2x < -10

Divide by two on both sides
2 < -5

2x + 3 > 7

Subtract three on both sides
2x > 4

Divide by two on both sides
x > 2


A. x < -5 or x > 2
4 0
3 years ago
Write an equation in slope-intercept form for the line that satisfies the following condition. slope 7, and passes through (5, 3
allsm [11]
Y = mx + b
slope(m) = 7
(5,30)...x = 5 and y = 30
now we sub and find b, the y int
30 = 7(5) + b
30 = 35 + b
30 - 35 = b
-5 = b

so ur equation is : y = 7x - 5 <==
7 0
3 years ago
What is 9x-7y=-7 in slope intercept form?
Novay_Z [31]
Slope intercept form is y = mx + b

So if you start with 9x - 7y = -7, the first thing you need to do is move the 9x to the other side of the equation by subtracting it from both sides.
       9x - 7y =      -7
       -9x          -9x

Now you have -7y = -9x -7

For the equation to be in slope intercept form now you should divide every term by the number in front of your y.  In this case divide every term by -7
    -<u>7y</u> =  <u>-9x</u>  <u>-7</u>
      -7      -7   -7

That leaves you with: y = 9x/7 + 1


4 0
3 years ago
What is the percent or change-----$84 to 12%
zubka84 [21]
<span>$84 to 12%
</span>10.08
 is the answer
6 0
3 years ago
Write an equation of the perpendicular bisector of the segment with the endpoints (8,10) and ( -4,2).
ale4655 [162]

Answer:

The required equation is:

y = -\frac{3}{2}x+9

Step-by-step explanation:

To find the equation of a line, the slope and y-intercept is required.

The slope can be found by finding the slope of given line segment. A the perpendicular bisector of a line is perpendicular to the given line, the product of their slopes will be -1 and it will pass through the mid-point of given line segment.

Given points are:

(x_1,y_1) = (8,10)\\(x_2,y_2) = (-4,2)

We will find the slope of given line segment first

m = \frac{y_2-y_1}{x_2-x_1}\\= \frac{2-10}{-4-8}\\=\frac{-8}{-12}\\=\frac{2}{3}

Let m_1 be the slope of perpendicular bisector then,

m.m_1 = -1\\\frac{2}{3}.m_1 = -1\\m_1 = \frac{-3}{2}

Now the mid-point

(x,y) = (\frac{x_1+x_2}{2} , \frac{y_1+y_2}{2})\\= (\frac{8-4}{2} , \frac{10+2}{2})\\=(\frac{4}{2}, \frac{12}{2})\\=(2,6)

We have to find equation of a line with slope -3/2 passing through (2,6)

The equation of line in slope-intercept form is given by:

y = m_1x+b

Putting the value of slope

y= -\frac{3}{2}x+b

Putting the point (2,6) to find the y-intercept

6 = -\frac{3}{2}(2)+b\\6 = -3+b\\b = 6+3 =9

The equation is:

y = -\frac{3}{2}x+9

7 0
3 years ago
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