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Cloud [144]
3 years ago
10

Please help with 3,4,5

Mathematics
1 answer:
krek1111 [17]3 years ago
4 0

Answer:

It is easy he will get 1$

Step-by-step explanation:

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Graph the equation. y = 2 sqrt. x
777dan777 [17]

A graphing calculator or spreadsheet program can do this for you. Below is a plot from the Desmos on-line graphing calculator.

3 0
3 years ago
A researcher selects all of the possible samples with n = 8 scores from a population and computes the mean, dividing by n, for e
Nadusha1986 [10]

Answer:

By the Central Limit Theorem, the average value for all of the sample means is 14.

Step-by-step explanation:

We use the central limit theorem to solve this question.

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, the sample means of size n can be approximated to a normal distribution with mean \mu and standard deviation, which is also called standard error s = \frac{\sigma}{\sqrt{n}}

If the population mean is μ = 14, then what is the average value for all of the sample means?

By the Central Limit Theorem, the average value for all of the sample means is 14.

3 0
4 years ago
144 coins are divided equally among some children. If there were 3 children fewer, each child would have 16 coins. How many chil
enot [183]

Answer:

12

Step-by-step explanation:

144/16=9

Each child gets sixteen coins if there are nine children.

9+3=12

There are three more children so there are twelve.

8 0
3 years ago
1.5c - 6 = 7.5 i need help with this problem and i have no one to help me
Lostsunrise [7]

Answer:

c=9

Step-by-step explanation:

Let's solve your equation step by step:

  1. add 6 on both sides
  2. divide 1.5 from the product of 6 and 7.5 (aka 13.5)
  3. you will get C
  4. put 9 in for C.
<h2>1.5c-6=7.5</h2>

1. 1.5c-6+6=7.5+6

1.5 1.5c=13.5

2.\frac{1.5c}{1.5c}=\frac{13.5}{1.5c}

3. C=9

1.5(9)-6=7.5

13.5-6=7.5

6 0
2 years ago
Explain why the prices were the same in 13 and 14
kifflom [539]

Answer:

Step-by-step explanation:

8 0
3 years ago
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