Initial velocity of the plane is Vo = 0.
acceleration a = 1.3 m/s2
total distance = 2.5 km = 2500m
time taken to reach 2.5 km with 1.3m/s^2 acceleration = t
S = Vo t + 0.5 a t^2
2500 = 0 + (0.5*1.3* t^2)
t^2 = 3846.15
t = 62 s
the maximum velocity plan can reach within 62 s is Vt
Vt = Vo + a t
Vt = 0 + (1.3*62)
Vt = 80.6 m/s
Since 80.6 m/s is greater than 75 m/s, plane can use this runway to takeoff with required speed.
Answer:
25
Step-by-step explanation:
25
(5)² = 25 OR √25 = 5
Answer:
3/4
Step-by-step explanation:
3*3=9
3*4=12
Answer:
A sinusoidal model would be used
The kind of function that have consistency in the periodic rate of change is the Average rate of changes
Step-by-step explanation:
The type of model that would be used is sinusoidal model and this is because there is periodic change in the values given ( i.e the rate of changes given )
For percentage rate of changes :
starting from 0.9% there is an increase to 1.3% then a decrease to 1.1% and a further decrease to 1% before an increase to 1.3% and another decrease to 1%
For Average rate of changes:
starting from 2.9 there is a decrease to 2.4, then an increase to 3.7 and another decrease to 3.1 followed by an increase to 3.6 and a decrease back to 3.2
This relation ( sinusoidal model ) is best suited for a linear model because there is a periodic rate of change in the functions
The kind of function that have consistency in the period rate of change is the Average rate of changes
Answer:
g o f = 
Step-by-step explanation:
Given
Required:
Find g o f
This is calculated as:
So:
![g(f(x)) = 2[ 16x^2 + 16x + 4)] - 4](https://tex.z-dn.net/?f=g%28f%28x%29%29%20%3D%202%5B%2016x%5E2%20%2B%2016x%20%2B%204%29%5D%20-%204)
