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just olya [345]
3 years ago
13

The distance a train travels d is proportional to a constant rate of speed r at different times t which equation shows the relat

ionship between the speed of the train and the distance traveled A r=dt B r=d+t C r=d-t D r=d/t
Mathematics
1 answer:
Anarel [89]3 years ago
6 0

Answer:

D

Step-by-step explanation:

d = rt so to isolate r you divide both sides by t, leaving you with r=d/t

its basically speed=distance/time, or s=d/t if that's more farmiliar to you

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14. The diagonals of square ABCD intersect at E. If AE = 2, find the perimeter of ABCD.
lutik1710 [3]

Answer:

B, 8\sqrt{2}

Step-by-step explanation:

Diagonals of a square are congruent so AC= 4

using pythagorean theorem we can then do x^{2} +x^{2}=4^{2}

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2 years ago
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Hope this helps!


7 0
3 years ago
If CDE ~ GDF, find ED
qaws [65]

Answer:

10

Step-by-step explanation:

\triangle CDE \sim \triangle GDF.. (given) \\\\\therefore \frac{CD}{GD} =\frac{DE}{DF}.. (csst) \\\\\therefore  \frac{15}{x+3} =\frac{3x+1}{4}\\\\ \therefore   \: 15 \times 4 = (x + 3)(3x + 1) \\  \\ \therefore   \: 60 = 3 {x}^{2}  + x + 9x + 3 \\  \\ \therefore  3 {x}^{2}  + 10x + 3 - 60 = 0 \\ \therefore  3 {x}^{2}  + 10x  - 57 = 0 \\ \therefore  3 {x}^{2}  + 19x - 9x  - 57 = 0 \\ \therefore   \: x(3x + 19) - 3(3x + 19) = 0 \\\therefore   \:  (3x + 19)(x - 3) = 0 \\ \therefore   \: 3x + 19 = 0 \:  \: or \:  \: x - 3 = 0 \\  \therefore   \: x =  -  \frac{19}{3}  \:  \: or \:  \: x = 3 \\  \because \: x \: can \: not \: be \:  - ve \\ \therefore   \: x = 3 \\ ED = 3x + 1 = 3 \times 3 + 1  \\ \huge \red{ \boxed{ ED= 10}}

7 0
3 years ago
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