Answer:
11 mm, 21 mm, and 16 mm.
Step-by-step explanation:
since 11+21>16, 11+ 16>21>11, You can form a triangle with 11,21,16
Answer: c.A is the set of rational numbers
Step-by-step explanation:
B ⊆ A means that every element of B is an element of A
B = { -13 , -9 , -7 , - 3 }
The element of B are negative integers , this mean that the element of A must also be integers therefore :
Option a is correct.
Option b is also correct
Rational numbers are numbers that can be express in the form a/b , examples are : 1/2 , 3/ 4 , 5/6 ...
clearly , this does not necessarily define A , so option c is the odd one out
A. The Least common multiple between 6 and 8 is 24, so you have to buy 4 packages of pens and 3 packages of pencils.
2. Since you bought 24 pens and 24 pencils, you have 48 pens and pencils in all
In a hand of 5 cards, you want 4 of them to be of the same rank, and the fifth can be any of the remaining 48 cards. So if the rank of the 4-of-a-kind is fixed, there are
possible hands. To account for any choice of rank, we choose 1 of the 13 possible ranks and multiply this count by
. So there are 624 possible hands containing a 4-of-a-kind. Hence A occurs with probability

There are 4 aces in the deck. If exactly 1 occurs in the hand, the remaining 4 cards can be any of the remaining 48 non-ace cards, contributing
possible hands. Exactly 2 aces are drawn in
hands. And so on. This gives a total of

possible hands containing at least 1 ace, and hence B occurs with probability

The product of these probability is approximately 0.000082.
A and B are independent if the probability of both events occurring simultaneously is the same as the above probability, i.e.
. This happens if
- the hand has 4 aces and 1 non-ace, or
- the hand has a non-ace 4-of-a-kind and 1 ace
The above "sub-events" are mutually exclusive and share no overlap. There are 48 possible non-aces to choose from, so the first sub-event consists of 48 possible hands. There are 12 non-ace 4-of-a-kinds and 4 choices of ace for the fifth card, so the second sub-event has a total of 12*4 = 48 possible hands. So
consists of 96 possible hands, which occurs with probability

and so the events A and B are NOT independent.
To find your answer you would divide 21 by 3 which would be 7, once you've got 7 you would multiply it by 9 which would give you the amount of old houses that there is which would be 63.