Answer:
m=4
Step-by-step explanation:
m = y2 - y1/x2 - x1
(y2=8, y1=0, x2= 2, x1=0)
m = y2 -y1/x2 - x1
= 8 - 0/2 - 0
= 8/2
=4
Answer:
A = 14 mm²
Step-by-step explanation:
The area (A) of a triangle is calculated as
A = 
bh ( b is the base and h the height )
Here b = 14 and h = 2 , then
A = × 14 × 2 = 7 × 2 = 14 mm²
Answer:
-25 plug in 6 for x and minus one
Step-by-step explanation:
Answer and Explanation:
Solution: The operation of concatenation for a set of string on p. and the set is
AB = {XY | X ∈ A and y ∈ B}.
We need to satisfy all these following properties to find out the standard set is closed under concatenation.
1- Union of two standard sets also belongs to the classic collection. For example, A and B are regular. AUB also belongs to a regular group.
2- Compliment of two standards set A and B are A’ and B’ also belonging to the standard set.
3- Intersection of two standards set A and B is A∩B is also a regular set member.
4- The difference between two regular sets is also standard. For example, the difference between A and B is A-B is also a standard set.
The closure of the regular set is also standard, and the concatenation of traditional sets is regular.
