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Nady [450]
3 years ago
13

A rectangle is 1/3 yd long and 2/3 yd wide

Mathematics
1 answer:
ICE Princess25 [194]3 years ago
3 0
It might be 2/9 sorry if it wasn’t
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What's the way to workout this problem
Nady [450]
It's simple multiplication
5 0
3 years ago
Read 2 more answers
Two airplanes left the same airport and arrived at the same destination at the same time. The first airplane left at 8:00 a.m. a
liberstina [14]
First plane: 496x
<span>Second plane:  558( x - 1/2) </span>

<span>Equation: 496x = 558( x - 1/2) </span>

<span>Solving  x = 9/2 ,  or  x = 4.5 hours.

Hope this helps.</span>
7 0
3 years ago
How do you find the first five terms of a sequence defined recursively
Blizzard [7]
Interesting question. Good to know for computer science.
Suppose you have a function like 
an = 3x - 2 Try the first couple
a1 = 3(1) - 2
a1 = 3 - 2
a1 = 1

a2 = 3(2) - 2
a2 = 6 - 2
a2 = 4 So each term differs by 3
a2 - a1 = 3

an = a_(n - 1) + 3
a3 = a2 + 3
a3 = 4 + 3 
a3 = 7

a4 = a3 + 3
a4 = 7 + 3
a4 = 10

a5 = a4+ 3
a5 = 10 + 3
a5 = 13

I'll do one more and then check it.
a6 = a5 + 3
a6 = 13 + 3
a6 = 16

a6 = 3x -2
a6 = 3*6 - 2
a6 = 18 - 2
a6 = 16 which checks.

So the general formula is
an = a_(n - 1) * k if you were multiplying or
an = a_(n - 1) + k if you were adding. The key thing is that you are working with the previous term.
6 0
2 years ago
A right triangle is formed in the first quadrant by the x- and y-axes and a line through the point (5, 3), as shown in the figur
Whitepunk [10]

The area of the triangle as a function of x is A = 3x^2/[2(x -5)] and the domain is x > 5

<h3>Write the area A of the triangle as a function of x</h3>

From the figure, we have the following points:

(0,y), (5,3), and (x,0)

Next, we calculate the slopes between the points.

This is calculated as follows:

  • Slope between (0,y) and (5,3) = [y - 3]/[0 - 5] = [3 - y]/5
  • Slope between (5,3) and (x,0) = [3 - 0]/[5 - x] = 3/[5 - x]

The slopes are equal.

So, we have:

[3 - y]/5 = 3/[5 - x]

Cross multiply

(3 - y)(5 -x) = 15

Divide by 5 - x

(3 - y) = 15/(5 -x)

This gives

y = 3 - 15/(5 -x)

This gives

y = [15- 3x - 15]/[5 - x]

Evaluate

y = 3x/(x - 5)

The area is calculated as:

Area = 1/2 * xy

So, we have:

Area = 1/2 * x * 3x/(x - 5)

Evaluate

Area = 3x^2/[2(x -5)]

Hence, the area of the triangle as a function of x is A = 3x^2/[2(x -5)]

<h3>The domain of the function</h3>

We have:

A = 3x^2/[2(x -5)]

Set the denominator > 0

2(x - 5) > 0

Divide by 2

x - 5 > 0

Add 5 to the sides

x > 5

Hence, the domain is x > 5

Read more about domains at:

brainly.com/question/2428614

#SPJ1

6 0
2 years ago
What is the value of the expression 4/2^-2?<br> a. ½<br> b. 1<br> c. 8<br> d. 16
Alexus [3.1K]
2^{-2} = \frac{1}{2^{2} } =  \frac{1}{4}

\frac{4}{2^{-2} } = \frac{4}{ \frac{1}{4} } = 4 ÷ \frac{1}{4} = 4*4= 16

The answer is D. 16
8 0
2 years ago
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