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Archy [21]
3 years ago
10

Gabrielle's age is two times Mikhail's age. The sum of their ages is 84. What is Mikhail's age?

Mathematics
2 answers:
nevsk [136]3 years ago
7 0
Let x be Gabrielle’s age
Let y be Mikhail’s age
X=2y and x+y=84 so...
X=2y and x=84-y so by substitution of x,
2y=84-y
3y=84
Y=28

So Mikhail is 28
And Gabrielle is 56
Dvinal [7]3 years ago
6 0

Answer:

28

Step-by-step explanation:

Mikhail's age:x

Gabrielle's age:2x

x+2x=84

3x=84

x=84÷3

x=28

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Answer:

<h2>Marianna is incorrect because x2</h2><h2>2x13 can be factored into two binomials</h2>

Step-by-step explanation:

ax^2+bx+c = 0

x=−1+√14 or x=−1−√14

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Now, we can solve each term for  

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x(x+2)=0

Now, we can solve each term for  

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x=0

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and

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x+2-2=0-2

x+0=-2

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3 years ago
( I WILL BE GIVING EXTRA POINTS AND BRAINLIEST TO WHO EVER HELPS ME!! :D)
KatRina [158]

Answer:

B I think

Step-by-step explanation:

Eight eighths in one cup. Took that and multiplied that and added the single eighth. Six sixths in one cup. Took that and multiplied that and added the single sixth again. Added the total up and got 10.2916666667. Rounded. Hope this helps!

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Problem page scott has scored 28, 22, and 29 points in his three basketball games so far. how many points does he need to score
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3 years ago
If a,b,c and d are positive real numbers such that logab=8/9, logbc=-3/4, logcd=2, find the value of logd(abc)
Eva8 [605]

We can expand the logarithm of a product as a sum of logarithms:

\log_dabc=\log_da+\log_db+\log_dc

Then using the change of base formula, we can derive the relationship

\log_xy=\dfrac{\ln y}{\ln x}=\dfrac1{\frac{\ln x}{\ln y}}=\dfrac1{\log_yx}

This immediately tells us that

\log_dc=\dfrac1{\log_cd}=\dfrac12

Notice that none of a,b,c,d can be equal to 1. This is because

\log_1x=y\implies1^{\log_1x}=1^y\implies x=1

for any choice of y. This means we can safely do the following without worrying about division by 0.

\log_db=\dfrac{\ln b}{\ln d}=\dfrac{\frac{\ln b}{\ln c}}{\frac{\ln d}{\ln c}}=\dfrac{\log_cb}{\log_cd}=\dfrac1{\log_bc\log_cd}

so that

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\log_da=\dfrac{\ln a}{\ln d}=\dfrac{\frac{\ln a}{\ln b}}{\frac{\ln d}{\ln b}}=\dfrac{\log_ba}{\log_bd}=\dfrac{\log_db}{\log_ab}

so that

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###

Another way to do this:

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\log_bc=-\dfrac34\implies b^{-3/4}=c\implies b=c^{-4/3}

\log_cd=2\implies c^2=d\implies\log_dc^2=1\implies\log_dc=\dfrac12

Then

abc=(c^{-4/3})^{9/8}c^{-4/3}c=c^{-11/6}

So we have

\log_dabc=\log_dc^{-11/6}=-\dfrac{11}6\log_dc=-\dfrac{11}6\cdot\dfrac12=-\dfrac{11}{12}

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Pie

Answer:

$13.38


Step-by-step explanation:

tax =7% x 12.50 = 7/100 x 12.5 = $0.875

Price to pay = $12.50 + $0.875 = $13.375 = $13.38


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