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Nina [5.8K]
3 years ago
14

Determine if the equation 1/3×y represents a proportional relationship​

Mathematics
1 answer:
Rudiy273 years ago
6 0

Answer:

Step-by-step explanation:

(1/3)y=y(1/3) is not an equation, it's just an expression.

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What is the equation of the line that passes through the point (-3,5) and has a slope of -2
wariber [46]

Answer:

equation: y=-4x-7

Step-by-step explanation:

y=-4x+b

solve for b using given coordinates on the line (-3, 5)

5=-4(-3)+b

b=-7


6 0
3 years ago
Read 2 more answers
Suppose that, in 1995, the weight of 16-year old males in the United States was normally distributed with a mean of 143 lbs and
seropon [69]

Answer:

Step-by-step explanation:

The null hypothesis is:

H0: μ(1995)=μ(2019)

The alternative hypothesis is:

H1: μ(1995)<μ(2019)

Because Roger wants to know if mean weight of 16-old males in 2019 is more than the mean weight of 16-old males in 1995 the test only uses one tail of the z-distribution.  It is not a  two-sided test because in that case the alternative hypothesis would be:  μ(1995)≠μ(2019).

To know the p-value, we use the z-statistic, in this case 1.89 and the significance level. Because the problem does not specify it, we will search for the p-value at a 5% significance level and at a 1%.

For a z of 1.89 and 5% significance level, the p-value is: 0.9744

For a z of 1.89 and 1% significance level, the p-value is: 0.9719

4 0
3 years ago
20x^2-30=4x solve for x
ankoles [38]

Answer:

x=1.3288 or -1.1288

Step-by-step explanation:

Given 20x^{2}-30=4x

    Subtract 4x from both sides

         20x^{2}-4x-30=0

Since we can factor out 2 from whole equation, let's factor out 2.

         2(10x^{2}-2x-15)=0

Divide with 2 on both sides

         10x^{2}-2x-15=0

We got the quadratic equation, we can solve for x using quadratic formula.

x=\frac{-b\pm\sqrt{b^{2}-4ac} } {2a}

x=\frac{2\pm\sqrt{2^{2}-4X10X(-15)} } {2X10}

x=\frac{2\pm\sqrt{604} }{20}

x=\frac{2\pm2\sqrt{151}}{20}

x=1.3288or-1.1288


8 0
3 years ago
Read 2 more answers
Factor <br> 5(x^2n-1)·(2x^3n 1)^2
nikdorinn [45]

I think I may be wrong check

5(x^2n-1)×(2x^3n-1) ^2

=20n3 x8 -20n2 x5 +20n x3 +20n x3 +5n x2-5

3 0
3 years ago
Use the following rules to graph and label the ordered pairs on a coordinate grid with at least 4 points on the coordinate plane
Sati [7]

Answer:

3

Step-by-step explanation:

I just had this question

3 0
2 years ago
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