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3 years ago

(6x²-x-1)/(x-1) How do I simplify this so it is not divided by anything?

Mathematics

1 answer:

a_sh-v [17]3 years ago

7 0

Simplify:

The equation is already simplified =====> (6x² - x - 1)/(x - 1)

Solve:

Solution (6x² - x - 1)/(x - 1) =======> 6x + 5 + 4/x - 1

Steps:

Apply Long Division on:

(6x² - x - 1)/(x - 1)

Divide:

(6x² - x - 1)/(x - 1):

(6x² - x - 1)/(x - 1) = 6x + 5x - 1/x - 1

= 6x + 5x - 1/x - 1

Divide:

5x - 1/x - 1

= 5 + 4/x - 1

Answer ======> 6x + 5 + 4/x - 1

Hope that helps!!!!! : )

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3 years ago

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The system of equations when been placed in a matrix yields

$\left[\begin{array}{ccc}650&-1\\120&1\end{array}\right]\left[\begin{array}{ccc}x\\y\end{array}\right] =\left[\begin{array}{ccc}-175\\25080\end{array}\right]$

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more variables and numbers.

Given the equation:

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Rearranging the equations gives:

650x - y = -175 and;

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Placing the equations in a matrix gives:

$\left[\begin{array}{ccc}650&-1\\120&1\end{array}\right]\left[\begin{array}{ccc}x\\y\end{array}\right] =\left[\begin{array}{ccc}-175\\25080\end{array}\right]$

The system of equations when been placed in a matrix yields

$\left[\begin{array}{ccc}650&-1\\120&1\end{array}\right]\left[\begin{array}{ccc}x\\y\end{array}\right] =\left[\begin{array}{ccc}-175\\25080\end{array}\right]$

Find out more on equation at: brainly.com/question/2972832

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1 year ago