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andrew11 [14]
3 years ago
13

Use the chain rule to find dw/dt. w = ln x2 + y2 + z2 , x = 7 sin(t), y = 9 cos(t), z = 6 tan(t)

Mathematics
1 answer:
DENIUS [597]3 years ago
3 0
By the chain rule,

\dfrac{\mathrm dw}{\mathrm dt}=\dfrac{\partial w}{\partial x}\dfrac{\mathrm dx}{\mathrm dt}+\dfrac{\partial w}{\partial y}\dfrac{\mathrm dy}{\mathrm dt}+\dfrac{\partial w}{\partial z}\dfrac{\mathrm dz}{\mathrm dt}

We have

\dfrac{\partial w}{\partial x}=\dfrac{2x}{x^2+y^2+z^2}
\dfrac{\partial w}{\partial y}=\dfrac{2y}{x^2+y^2+z^2}
\dfrac{\partial w}{\partial z}=\dfrac{2z}{x^2+y^2+z^2}

\dfrac{\mathrm dx}{\mathrm dt}=7\cos t
\dfrac{\mathrm dy}{\mathrm dt}=-9\sin t
\dfrac{\mathrm dz}{\mathrm dt}=6\sec^2t

So we have

\dfrac{\mathrm dw}{\mathrm dt}=\dfrac2{x^2+y^2+z^2}\left(7x\cos t-9y\sin t+6z\sec^2t\right)
\dfrac{\mathrm dw}{\mathrm dt}=\dfrac{2\left(49\sin t\cos t-81\cos t\sin t+36\tan t\sec^2t\right)}{49\sin^2t+81\cos^2t+36\tan^2t}
\dfrac{\mathrm dw}{\mathrm dt}=\dfrac{8\sin t(9-16\cos^4t)}{\cos t(36+13\cos^2t+32\cos^4t)}
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Find the distance between the origin and the points (-8,4)​
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Hi, I'm happy to help!

To solve this, we need to find the distance from the origin to the y coordinate value, x coordinate value, then use the Pythagorean Theorem.

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First, let's find the x coordinate distance change. We move from the x coordinate 0, to the x coordinate -8, <u>so we move 8 x units.</u>

Next, let's find the y coordinate distance change. We move from the y coordinate 0, to the y coordinate 4, <u>so we move 4 y units.</u>

Now that we have these two leg lengths, let's imagine this as a right triangle. Moving from the origin, we draw a line from (0,0), to (-8,0). Then, we draw a line from (-8,0) to (-8,4). Now, draw a direct line from (0,0), to (-8,4). We have the length of the first(8) and second(4) lines, and we need to find the third line length to find our answer. To do this, we use the Pythagorean Theorem, which states that a²+b²=c². This says that, in a right triangle, the square of the two shorter lengths equals the square of the longest length. The longest length is what we are solving for.

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I hope this was helpful, keep learning! :D

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