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GuDViN [60]
2 years ago
11

Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used. Match the estimated value of each express

ion with its position on the number line. plz help​

Mathematics
1 answer:
DIA [1.3K]2 years ago
8 0

Answer:

DEAC

Step-by-step explanation:

You might be interested in
Which two consecutive whole numbers would 341 be located?
marysya [2.9K]
The first number is 170
The second number is 171
Step-by-step explanation:
Let the first number be x^3 and the second number be x^3+1
The sum of the two is 341
X^3+x^3+1=341
2x^3+1=341
Substrate 1 from both sides
2x^3=341-1
8 0
3 years ago
Find ‘x’ in:- <br> x:6 :: 5 : 11
melomori [17]

Answer:

<h3>x:6 :: 5 : 11</h3>

x = 6*5/11=30/11

7 0
2 years ago
The number of nails of a given length is norm ally distributed with a mean length of 5.00 in, and a standard deviation of 0.03 i
natta225 [31]

Answer:

120·(1 - Ф((5.03 - 5)/0.03)) ≈ 20 nails

6 0
3 years ago
Part 1 out of 2
PolarNik [594]

Answer:

<u>The expression is 6v² + 6v - 120</u>

Step-by-step explanation:

v = Car's speed

Let's write the expression for 6 times the square of a car's speed plus 6 times the car's speed  minus 120, this way:

6v² = 6 times the square of a car's speed

6v - 120 = 6 times the car's speed  minus 120

Now, let's add the operator (+):

6v² (6 times the square of a car's speed) + 6v - 120 (6 times the car's speed  minus 120)

<u>The expression is 6v² + 6v - 120</u>

3 0
3 years ago
Which are the maximum values ? I will add a picture please help
Alik [6]

Answer:

58 at the point (9,8)

7 at the point (1, 1)

Step-by-step explanation:

The maximum points will be found in the vertices of the region.

Therefore the first step to solve the problem is to identify through the graph, the vertices of the figure.

The vertices found are:

(1, 10)

(1, 1)

(9, 5)

(9, 8)

We look for the values of x and y belonging to the region, which maximize the objective function f(x, y) = 2x + 5y. Therefore we look for the vertices with the values of x and y higher.

(1, 10), (9, 5), (9, 8)

Now we substitute these points in the objective function and select the one that produces the highest value for f (x, y)

f(1, 10) = 2(1) + 5(10) = 52\\\\f(9, 5) = 2(9) + 5(5) = 43\\\\f(9, 8) = 2(9) + 5(8) = 58

The point that maximizes the function is:

(9, 8) with f(9, 8) = 58

Then the value that produces the minimum of f(x, y) is (1, 1)

f(1, 1) = 2(1) + 5(1) = 7

5 0
2 years ago
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