All categories

3 years ago

For 6 days in a row, alyssa recorded the total amount of rain

Mathematics

1 answer:

Anna [14]3 years ago

5 0

Answer

if your looking for an answer try to be smart and actually show a picture I cant do nothing with just a name thats how we us experts find answers pictures.

Step-by-step explanation:

You might be interested in

Simplify. Write answers with positive exponents only.

allochka39001 [22]

Answer:

The answer to your question is 2⁸x²⁰ y²⁴ or 256x²⁰y²⁴

Step-by-step explanation:

Data

(2x³y³)⁴ (2x²y³)⁴

To solve this problem, use the law of exponents.

1.- Use the law of Power of a power rule

(2x³y³)⁴ (2x²y³)⁴ = (2⁴x¹²y¹²) (2⁴x⁸y¹²)

2.- Use the multiplication rule

(2⁴x¹²y¹²) (2⁴x⁸y¹²) = 2⁸x²⁰ y²⁴

3.- The answer is 2⁸x²⁰y²⁴ or we can simplify more like

256x²⁰y²⁴

7 0

3 years ago

Someone please help!!!!

Ber [7]

Answer:

Step-by-step explanation:

3 0

3 years ago

24=3(n-5) solve for n

mario62 [17]

Answer:

n = 13

Step-by-step explanation:

24 = 3 (n-5)

3n - 15 = 24

3n = 24 +15

3n = 39

n = 39/3

n = 13

6 0

3 years ago

Read 2 more answers

45 of the 80 children in the club or girls what was the ratio of boys to girls in the club?

Oxana [17]

There are 80 children. 45 of them are girls. The amount of boys is equal to:

$80-45 = 35$

That means there are 45 girls and 35 boys.

The ratio of boys to girls is: $35:45$

Simplify:

$35 \div 5 = 7 \\ 45 \div 5 = 9 \\ \\35:45 \rightarrow 7:9$

Your answer is 7:9

5 0

3 years ago

Find (a) arc length and (b) Area of a sector.

barxatty [35]

Answer:

a) 29.45 cm (2 dp)

b) 220.89 cm² (2 dp)

Step-by-step explanation:

<u>Formula</u>

$\textsf{Arc length}=r \theta$

$\textsf{Area of a sector}=\dfrac{1}{2}r^2 \theta$

$\quad \textsf{(where r is the radius and}\:\theta\:{\textsf{is the angle in radians)}$

<u>Calculation</u>

Given:

$\theta=\dfrac{5 \pi}{8}$
r = 15 cm

$\begin{aligned}\implies \textsf{Arc length} & =r \theta\\& = 15\left(\dfrac{5 \pi}{8}\right)\\& = \dfrac{75}{8} \pi \\& = 29.45\: \sf cm\:(2\:dp)\end{aligned}$

$\begin{aligned} \implies \textsf{Area of a sector}& =\dfrac{1}{2}r^2 \theta\\\\ & = \dfrac{1}{2}(15^2) \left(\dfrac{5 \pi}{8}\right)\\\\& = \dfrac{225}{2}\left(\dfrac{5 \pi}{8}\right)\\\\ & = \dfrac{1125}{16} \pi \\\\& = 220.89 \: \sf cm^2\:(2\:dp)\end{aligned}$

5 0

2 years ago