The equation that describes the greatest horizontal length, H, in terms of the greatest vertical length, V is H = 2V + 3.
<h3>How to compute the equation?</h3>
Your information is incomplete. Therefore, an overview will be given.
Let's assume that the value of the horizontal length is 3 plus twice the value of the the vertical length. This will be:
H = (2 × V) + 3
H = 2V + 3
In conclusion, the equation is H = 2V + 3.
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The formula for distance is equal to:
d = v * t
where d is distance, v is velocity or speed, and t is
time
Since the distance travelled by the two airplane is
similar, therefore we can create the initial equation:
v1 * t1 = v2 * t2
We know that v1 = 496, and v2 = 558 so:
496 t1 = 558 t2
or
x = 558 t2 / 496
We also know that airplane 1 travelled 30 minutes (0.5
hours) earlier than airplane 2, therefore:
x = t2 + 0.5
Hence,
496 (t2 + 0.5) = 558 t2
496 t2 + 248 = 558 t2
t2 = 4 hours
x = t2 + 0.5 = 4 + 0.5
x = 4.5 hours
So the equation is:
x = 558 t2 / 496
And the first plane travelled:
x = 4.5 hours
Answer:
i dont understand either
Step-by-step explanation:none
