Picture related to the question is attached below
Answer:
Kendra should have divided by 2 instead of multiplying by 2
Step-by-step explanation:
40 percent = percentage who plan to attend
100% = total percentage of student
From the question ;
When reducing percentages, division is employed and this the equation should be :
40/2 ÷ 100/2
40/2 * 2/100
20 * 1/50
20/50
= 0.4
0.4 * 50
= 20 students
A) For the equation
, the slope is
.
Slope-intercept form is y = mx + b, where m is slope and b is the y-intercept. This means that if
, the slope is
.
B) Since this equation is in the same form, you just find what m is equal to.
Since
, that's the slope.
For the solution, set
equal to
, so it would be put together like this:
![y=[tex]- \frac{1}{2}x+3=2x-4\\ -\frac{1}{2}=2x-7\\ 1\frac{1}{2}x=-7\\ x=-4.66667](https://tex.z-dn.net/?f=y%3D%5Btex%5D-%20%5Cfrac%7B1%7D%7B2%7Dx%2B3%3D2x-4%5C%5C%20-%5Cfrac%7B1%7D%7B2%7D%3D2x-7%5C%5C%201%5Cfrac%7B1%7D%7B2%7Dx%3D-7%5C%5C%20x%3D-4.66667)
So your answer is
-4.667.
Answer: Lin is the most consistent and I would want to have them on my team.
Why is this? Because their dots are more clustered together compared to the other distributions. Elena may have made the most shots (9) at one point, but her data set is very spread out and more unpredictable. The more spread out a data set is, the higher the variance and standard deviation. The range is also affected by how spread out the data set is since
range = max - min
So in a rough sense, the range can be used to estimate the variance and standard deviation. Though more accurate formulas are usually the better way to go.
Answer: From what you wrote the I think the ball is drop
At time 0 you are 7 meters above ground
You basically just need to solve for
1.5 =7t-4.9t^2
by rearrange the equation you get
4.9t^2-7t+1.5=0
by using Quadratic Formula
t=1.166s
Any number larger than 36 would be a counter examples.
When n is equal to 36, both sides of the inequality are equal to 216. As you get larger than 36 the right side is larger than the left side. Therefore, the inequality is not true.
