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sveticcg [70]
3 years ago
7

Fifty-six biscuits are to be fed to 10 pets; each pet is either a cat or a dog. each dog is to get six biscuits, and each cat is

to get five. how many dogs are there? (try to find a solution without performing any algebra.
Mathematics
1 answer:
Stella [2.4K]3 years ago
6 0

Fifty-six biscuits are to be fed to 10 pets; each pet is either a cat or a dog. each dog is to get six biscuits, and each cat is to get five. how many dogs are there?

Answer: There are 6 dogs  

Explanation:

Total number of biscuits = 56

Total number of Pets = 10

Now each dog is to be given 6 biscuits and each cat is to be given 5 biscuits.

Now if there are 6 dogs and each is to be given 6 biscuits and total biscuits given to 6 dogs = 6 x 6 =36

and there are 4 cats and each is to be given 5 biscuits and total biscuits given to 4 dogs = 4 x 5 =20

Therefore, total biscuits given to 6 dogs and 4 cats is 36+20= 56

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2 years ago
PLEASE HELP! WILL MARK BRAINLIEST!
julsineya [31]
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7 0
3 years ago
Read 2 more answers
Makayla and Caroline go to the movie theater and purchase refreshments for their friends. Makayla spends a total of $49.00 on 9
gizmo_the_mogwai [7]

Answer:

Let the cost of each popcorn bag be x and cost of each  drink be y

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According to Question

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Similarly , cost of 3 popcorn = 3 x

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According to Question

3 x+ 3 y= $ 17.25...................equation(2)

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put value of y  in any equation (2)

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AleksandrR [38]
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