Evaluate the expression x-y3 ;x =27,y=3

1 answer:

5 0

I think it might be 18 sorry if im wrong

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olchik [2.2K]

Answer:

132

Step-by-step explanation:

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3 years ago

Vladimir79 [104]

A will be the right answer

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3 years ago

defon

$\begin{gathered} x^2+24=14x \\ x^2-14x+24=0 \end{gathered}$

Therefore,

$\begin{gathered} x^2-14x+24=0 \\ x^2-2x-12x+24=0 \\ x(x-2)-12(x-2)=0 \\ (x-2)(x-12)=0 \\ x=2 \\ or\text{ } \\ x=12 \end{gathered}$

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1 year ago

goldenfox [79]

Answer:

1.) Domain: [-2, 1] Range: [1, 2] 2.) Domain: [-1, 2] Range: [-2, 2]

Step-by-step explanation:

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3 years ago

kifflom [539]

Answer:

a³-b³= (a-b)(a²+ab+ b²)

Step-by-step explanation:

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3 years ago