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RideAnS [48]
3 years ago
7

-7 2/3 + (-5 1/2) + 8 3/4 = A.-21 11/12 B.-4 5/12 C. -4 2/4 D. 6 7/12

Mathematics
2 answers:
Elena L [17]3 years ago
6 0

Answer:

B

Step-by-step explanation:

kirza4 [7]3 years ago
5 0

Answer: B. -4 5/12

Step-by-step explanation:

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Give that 5x=3(mod7)find x
pychu [463]

Answer Below!

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5 0
3 years ago
A small square pyramid of height 6 cm was removed from the top of a large square pyramid of height 12cm forming the solid shown.
Semmy [17]

Answer:

15,872 mm³

Step-by-step explanation:

given:

A small square pyramid of height 6 cm was removed from the top of a large square pyramid of height 12cm forming the solid shown.

Find:

the exact volume of the solid

solution:

volume of square base pyramid = (base area)² * h/3

where total h = 12 cm

height of top pyramid (ht)= 6 cm

height of bottom pyramid (hb) = 6 cm

bottom volume =  total volume - the volume on top

so,

total volume = 1/3 (base area)² h

                     = 1/3 (8*8)² * 12

                     = 16,384 mm³

volume on top = 1/3 (top base area)² h

                         = 1/3 (4*4)² * 6

                         = 512 mm³

finally: get the bottom volume:

bottom volume =  total volume - the volume on top

bot. vol = 16,384 mm³ - 512 mm³

             = 15,872 mm³

therefore,

the volume of the cut  pyramid base = 15,872 mm³

5 0
3 years ago
Read 2 more answers
I NEED THIS RN PLEASE
Lerok [7]

Answer:

The answer is C, 3 to 2

Step-by-step explanation:

This is because 12 divided by 4 is 3 and 8 divided by 4 is 2 so yhe ratio is 3 to 2. Hope it helps.

3 0
3 years ago
Solve<br> 4(-5)(-2)(-3)<br> show your work&lt;3<br> no links
laila [671]

Answer:

<h2><em><u>-120</u></em></h2>

Step-by-step explanation:

4(-5)(-2)(-3)

= -20 × 6

= <em><u>-120 (Ans)</u></em>

5 0
2 years ago
Read 2 more answers
Write the augmented matrix for the given system. x + 3y + 5z = -3 -5y + 3z = -8 -8z = -6
Phantasy [73]

\begin{pmatrix} 1  & 3 &  5 & | &  -3& \\ 0 & 5 & 3 & | &  -8 \\  0 & 0 & -8 & | & -6 \end{pmatrix}

5 0
3 years ago
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