Question

Random samples of people in Canada and people in Sweden are used to estimate the difference between the two countries in the proportion of people who have seen a hockey game (at any level) in the past year. Let group 1 be people from Canada and group 2 be people from Sweden.

Answer 1

Answer:

The point estimate of the difference between population proportions is $\hat p_{1}-\hat p_{2}$.

Step-by-step explanation:

The complete question is:

Random samples of people in Canada and people in Sweden are used to estimate the difference between the two countries in the proportion of people who have seen a hockey game (at any level) in the past year.

Let group 1 be people from Canada and group 2 be people from Sweden.

Give notation for the quantity that gives the best estimate. Your answer should be an expression composed of symbols:.

Solution:

In statistic, point estimation comprises of the use of sample data to estimate a distinct data value (known as a point estimate) which is to function as a "best guess" or "best estimate" of an unidentified population parameter.  

The point estimate of the population mean (µ) is the sample mean ($\bar x$).

In this case, we need to estimate the difference between the two countries in the proportion of people who have seen a hockey game in the past year.

So, the parameter to be estimated is the difference between the two proportions.

It is provided that:

1 : people from Canada

2 : people from Sweden

The point estimate of a population proportion (p) is the sample proportion   ($\hat p$).

So, the point estimate of the difference between population proportions (p₁ and p₂) is,

Point estimate of (p₁ - p₂) = $\hat p_{1}-\hat p_{2}$.

Thus, the point estimate of the difference between population proportions is $\hat p_{1}-\hat p_{2}$.