Can somebody please help me with this question?!?!?!

Marianna [84]

I'm just eyeballing the chart but imma guess .9

7 0

4 years ago

Using the following equation, find the center and radius of the circle. You must show all work and calculations to receive credi

Oxana [17]

Answer:

Center: (-2, 4)

Radius: 4

Step-by-step explanation:

To find the centre and radius, we require to identify g , f and c

By comparing the coefficients of 'like terms' in the given equation with the general form.

2g = 4 → g = 2 , 2f = -8 → f = -4 and c = 4 → center=(−g,−f)=(−2,4)

radius = √22+(−4)2−4= √4+16−4=4

Center: (-2, 4)

Radius: 4

Hope This Helps! :)

8 0

3 years ago

What statement best explains The relationshipBetween numbersDivisible by 5 and 10

kykrilka [37]

Answer:

a number that is divisible by 10 is also divisible by 5 because 5 is a factor of 10.

Step-by-step explanation:

Given : Statement 'The relationship between numbers divisible by 5 and 10'.

To find : What statement BEST explains the statement?

Solution :

First we study the divisibility rules,

Rule for the number divisible by 5 is that number must end in 5 or 0.

Rule for the number divisible by 10 is that number need to be even and divisible by 5, as the prime factors of 10 are 5 and 2 and the number to be divisible by 10, the last digit must be a 0.

According to the divisibility rules Option D is correct.

Therefore, The correct statement explains the relationship between numbers divisible by 5 and 10 is a number that is divisible by 10 is also divisible by 5 because 5 is a factor of 10.

4 0

3 years ago

Separable differential equation y’ln^2y+ysqrtx=0 y(0)=e

Maksim231197 [3]

By applying the theory of separable ordinary differential equations we conclude that the solution of the differential equation $\frac{dy}{dx} \cdot (\ln y)^{2} + y\cdot \sqrt{x} = 0$ with y(0) = e is $y = e^{\sqrt [3]{-2\cdot x^{\frac{3}{2} }+1}}$ .

<h3>How to solve separable differential equation</h3>

In this question we must separate each variable on each side of the equivalence, integrate each side of the expression and find an explicit expression (y = f(x)) if possible.

$\frac{dy}{dx} \cdot (\ln y)^{2} + y\cdot \sqrt{x} = 0$

$(\ln y)^{2}\,dy = -y \cdot \sqrt{x}\, dx$

$-\frac{(\ln y)^{2}}{y}\, dy = \sqrt{x} \,dx$

$-\int {\frac{(\ln y)^{2}}{y} } \, dy = \int {\sqrt{x}} \, dx$

If u = ㏑ y and du = dy/y, then:

$-\int {u^{2}\,du } = \int {x^{\frac{1}{2} }} \, dx$

$-\frac{1}{3}\cdot u^{3} = \frac{2\cdot x^{\frac{3}{2} }}{3} + C$

$u^{3} = -2\cdot x^{\frac{3}{2} } + C$

$(\ln y)^{3} = - 2\cdot x^{\frac{3}{2} } + C$

$C = (\ln e)^{3}$

$C = 1$

And finally we get the explicit expression:

$\ln y = \sqrt [3]{-2\cdot x^{\frac{3}{2} }+ 1}$

$y = e^{\sqrt [3]{-2\cdot x^{\frac{3}{2} }+1}}$

By applying the theory of separable ordinary differential equations we conclude that the solution of the differential equation $\frac{dy}{dx} \cdot (\ln y)^{2} + y\cdot \sqrt{x} = 0$ with y(0) = e is $y = e^{\sqrt [3]{-2\cdot x^{\frac{3}{2} }+1}}$ .

To learn more on ordinary differential equations: brainly.com/question/14620493

#SPJ1

6 0

2 years ago

Socks. help with this question

Yuri [45]

Get photo math! It will solve it for you

6 0

3 years ago