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3 years ago

Can somebody please help me with this question?!?!?!

Mathematics

1 answer:

scoray [572]3 years ago

6 0

I don't think there's any answer. It says that the absolute value of x-7 is negative 2, but an absolute value is always positive. So there's no value for x that can make the equation a true statement.

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If I have a floor that is 100 3/4 feet by 75 1/2 what is the area

Vlad [161]

The area, assuming is a rectangular floor, is their product.

so simply convert the mixed to improper and get their product.

$\bf \stackrel{mixed}{100\frac{3}{4}}\implies \cfrac{100\cdot 4+3}{4}\implies \stackrel{improper}{\cfrac{403}{4}}
\\\\\\
\stackrel{mixed}{75\frac{1}{2}}\implies \cfrac{75\cdot 2+1}{2}\implies \stackrel{improper}{\cfrac{151}{2}}\\\\
-------------------------------\\\\
\cfrac{403}{4}\cdot \cfrac{151}{2}\implies \cfrac{403\cdot 151}{4\cdot 2}\implies \cfrac{60853}{8}\implies 7606\frac{5}{8}~ft^2$

6 0

3 years ago

The table shows the number of cell phone towers a

Olin [163]

Answer:

The correct option is;

B. Yes. The ratios of towers to customers (thousands) are all equivalent to a unit rate of 52 Towers/(Thousand customers)

Step-by-step explanation:

The given data can be presented as follows;

Cell Phone Towers

Customer (thousands) ${}$ Towers

1) 5.25 ${}$ 273

2) 6.25 ${}$ 325

3) 7.25 ${}$ 377

4) 9.25 ${}$ 481

From the given data, we have the ratio Towers/Customer (thousands) given as follows;

For 1), we have;

273 Towers/(5.25 thousands customers) = 52 Towers/(Thousand customer)

For 2), we have;

325 Towers/(6.25 thousands customers) = 52 Towers/(Thousand customer)

For 3), we have;

377 Towers/(7.25 thousands customers) = 52 Towers/(Thousand customer)

For 4), we have;

481 Towers/(9.25 thousands customers) = 52 Towers/(Thousand customer)

Therefore, the ratios of towers to customers (thousands) all have the same equivalent unit rate of 52 Towers/(thousand customers).

6 0

2 years ago

Nina purchased apples and strawberries. She purchased a total of 9 pounds of fruit and spent a total of $16.35. Strawberries cos

irina [24]

Answer:

4 pounds of strawberries and 5 pounds of apples are bought.

Step-by-step explanation:

Given:

Total number of pounds of fruit = 9 pounds

Total money spent = $16.35

Cost of 1 pound of strawberry = $1.60

Cost of 1 pound of apple = $1.99

Let 'x' pounds of strawberries and 'y' pounds of apples are bought.

So, as per question:

The sum of the pounds is 9. So,

$x+y=9\\\\y=9-x----1$

Now, total sum of the fruits is equal to the sum of 'x' pounds of strawberries and 'y' pounds of apples. So,

$1.60x+1.99y=16.35----2$

Now, plug in the 'y' value from equation (1) in to equation (2). This gives,

$1.60x+1.99(9-x)=16.35\\\\1.60x+17.91-1.99x=16.35\\\\Combining\ like\ terms, we get:\\\\1.60x-1.99x=16.35-17.91\\\\-0.39x=-1.56\\\\x=\frac{-1.56}{-0.39}=4\ pounds$