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VLD [36.1K]
3 years ago
14

B+c= someone help please

Mathematics
1 answer:
trasher [3.6K]3 years ago
4 0

Answer:

Is there any more to the problem but BC could be the answer it depends on what your supposed to be looking for

Step-by-step explanation:

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A random sample of of 100 voters in a town is selected, and 24 are found to support an annexation suit. Find the 96% confidence
lbvjy [14]

Answer: 0.24 +/- 0.088 = (0.152, 0.328)

Step-by-step explanation:

The point estimate p is given by;

p= 24/ 100 = 0.24

Z value for 96% confidence interval is 2.05

The solution for the given confidence interval is derived using the equation

p +/- z√(pq/n)

Where p = 0.24 q= 1-p = 0.76, n=100 z= 2.05

= 0.24 +/- 2.05√(0.24×0.76/100)

= 0.24 +/- 2.05(0.0427)

=0.24 +/- 0.088

= ( 0.152, 0.328)

6 0
3 years ago
Look at the incomplete multiplication problem below.
USPshnik [31]
So I'm assuming the answers have to be the same?? if that's the case, 457×32=15904 so you would subtract 994 from 15904. That means the answer is 14,910. I hope this helped!
4 0
3 years ago
Read 2 more answers
I will give brainliest<br> 7k+8=2k-37<br> Show work pleaseeeee
Artyom0805 [142]

Answer:

k = -9

Step-by-step explanation:

subtract 2k from both sides

_5k+8= -37

subtract 8

_5k = -45

divide by 5

_k = -9

6 0
2 years ago
Read 2 more answers
Retail price: $745; discount rate: 12.5% what is the discount?
Mariulka [41]

Answer:

mmmmmmmm

Step-by-step explanation:

the answer ................

7 0
3 years ago
Anyone can help me solve this equation using cross multiplying
Natali5045456 [20]

9514 1404 393

Answer:

  x = 1 or 5

Step-by-step explanation:

The notion of "cross-multiplying" is the idea that the numerator on the left is multiplied by the denominator on the right, and the numerator on the right is multiplied by the denominator on the left. This looks like ...

  \displaystyle \frac{x-1}{7}=\frac{2x-2}{3x-1}\ \longrightarrow\ (x-1)(3x-1)=(7)(2x-2)

Then the solution proceeds by eliminating parentheses, and solving the resulting quadratic equation.

  3x^2-4x+1=14x-14\\\\3x^2-18x+15=0\qquad\text{subtract $14x-14$}\\\\x^2-6x+5=0 \qquad\text{divide by 3}\\\\(x-1)(x-5)=0\qquad\text{factor}\\\\x\in\{1,5\}

_____

<em>Comment on "cross multiply"</em>

Like a lot of instructions in Algebra courses, the idea of "cross multiply" describes <em>what the result looks like</em>. It doesn't adequately describe how you get there. The <em>one and only rule</em> in solving Algebra problems is "<em>whatever is done to one side of the equation must also be done to the other side of the equation</em>." If you multiply one side by one thing and the other side by a different thing, you are violating this rule.

What looks like "cross multiply" is really "<em>multiply by the product of the denominators</em> and cancel like terms from numerator and denominator." Here's what that looks like with the intermediate steps added.

  \displaystyle \frac{x-1}{7}=\frac{2x-2}{3x-1}\\\\\frac{x-1}{7}\times7(3x-1)=\frac{2x-2}{3x-1}\times7(3x-1)\\\\(x-1)(3x-1)=(2x-2)(7)\qquad\textit{looks like}\text{ cross multiply}

8 0
2 years ago
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