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4 years ago

14

B+c= someone help please

1 answer:

trasher [3.6K]4 years ago

4 0

Answer:

Is there any more to the problem but BC could be the answer it depends on what your supposed to be looking for

Step-by-step explanation:

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What does ¿cual? mean in Spanish

masya89 [10]

Its translates which
Hopes this helps

5 0

3 years ago

Find the velocity and position vectors of a particle that has the given acceleration and the given initial velocity and position

stira [4]

Answer:

$v(t) = (2t+1) \mathbb{i} +3t^2 \mathbb{j} +4t^3 \mathbb{k}$

$r(t) = (t^2+t) \mathbb{i} +(t^3+2) \mathbb{j} +(t^4 - 3) \mathbb{k}$

Step-by-step explanation:

The velocity vector is the integral of the acceleration vector i.e.

$v(t) = \int a(t) dt$

$v(t) = \int (2 \mathbb{i}+6t \mathbb{j} 12t^2 \mathbb{k}) dt$

$v(t) = 2t \mathbb{i}+3t^2 \mathbb{j} 4t^3 \mathbb{k} + C_1$

When $t=0$ , $v(0) = \mathbb{i}$ . Inserting these values in $v(t)$ ,

$C_1= \mathbb{i}$

$v(t) = 2t \mathbb{i}+3t^2 \mathbb{j} 4t^3 \mathbb{k} + \mathbb{i}$

$v(t) = (2t+1) \mathbb{i}+3t^2 \mathbb{j} 4t^3 \mathbb{k}$

The position vector is the integral of the velocity vector i.e.

$r(t) = \int v(t) dt$

$r(t) = \int ((2t+1) \mathbb{i}+3t^2 \mathbb{j} 4t^3 \mathbb{k}) dt$

$r(t) = (t^2+t) \mathbb{i}+t^3 \mathbb{j} t^4 \mathbb{k} + C_2$

When $t=0$ , $r(t) =2\mathbb{j}-3\mathbb{k}$ . Inserting these values in $r(t)$ ,

$C_2=2\mathbb{j}-3\mathbb{k}$

$r(t)= (t^2+t) \mathbb{i}+t^3 \mathbb{j}+ t^4 \mathbb{k} + 2\mathbb{j}-3\mathbb{k}$

$r(t) = (t^2+t) \mathbb{i}+(t^3+2) \mathbb{j}+ (t^4-3) \mathbb{k}$

5 0

4 years ago

The local theater sells tickets to its plays at a rate of $38 each. Patrons who attend multiple shows are encouraged to buy an a

harina [27]

Answer:

Roger

Step-by-step explanation:

<u>Without Membership</u>

<em>Roger: $228</em>

<em>Grace: $152</em>

<u>With Membership</u>

<em>Roger: $200</em>

<em>Grace: $160</em>

3 0

2 years ago

In which cell structure does MOST of the process of cellular respiration take place?A.nucleusB.vacuoleC.cell wallD.mitochondrion

Zielflug [23.3K]

Mitochondria, therefore D

5 0

3 years ago

Alma is estimating the proportion of students in her school district who, in the past month, read at least 1 book. From a random

Maurinko [17]

Answer:

D)

$(0.64 +1.645 \sqrt{\frac{0.64(0.36)}{50} })$

90 percent confidence interval for the proportion of all students in her district who read at least 1 book last month

(0.52846 , 0.75166)

Step-by-step explanation:

<u><em>Step:-1</em></u>

Given that the random sample size 'n' = 50

The sample proportion

$p^{-} = \frac{32}{50} = 0.64$

90 percent confidence interval for the proportion of all students in her district who read at least 1 book last month

$(p^{-} - Z_{0.90} \sqrt{\frac{p(1-p)}{n}, } , p^{-} +Z_{0.90} \sqrt{\frac{p(1-p)}{n} })$

<u><em>Step(ii):-</em></u>

Level of significance = 0.90

Z₀.₉₀ = 1.645

$(0.64 - 1.645 \sqrt{\frac{0.64(1-0.64)}{50}, } , 0.64 +1.645 \sqrt{\frac{0.64(1-0.64)}{50} })$

$(0.64 - 1.645 \sqrt{\frac{0.64(0.36)}{50}, } , 0.64 +1.645 \sqrt{\frac{0.64(0.36)}{50} })$

(0.64 -1.645(0.06788) , (0.64 + 1.645(0.06788)

(0.52846 , 0.75166)

<u><em>Final answer:-</em></u>

90 percent confidence interval for the proportion of all students in her district who read at least 1 book last month

(0.52846 , 0.75166)

5 0

3 years ago