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zubka84 [21]
2 years ago
10

Please help lol1 (4.3) + 23 + 3 = ???​

Mathematics
2 answers:
Alecsey [184]2 years ago
8 0

Answer:

Step-by-step explanation:

Degger [83]2 years ago
4 0

Answer:

30.3

Step-by-step explanation:

  • (20 + 3) + (4 + 0.3) + (3)
  • 20 + (3 + 4 + 3) + (0.3)
  • 20 + 10 + 0.3
  • 30.3
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What are the solutions to the equation 9x2 = 49, rounded to the nearest tenth?
Maksim231197 [3]
9x 2=49
9x=24.5
x=2.72222
5 0
3 years ago
Somebody please help meee!!!!
Stels [109]

Answer:

12 m³

Step-by-step explanation:

4 x 2 x 1.5 = x

4 x 2 = 8

1.5 x 8 = 12

5 0
3 years ago
Read 2 more answers
Solve differential equation:<br><br> y'''+4y''-16y'-64y=0 y(0)=0, y'(0)=26, y''(0)=-16
Ipatiy [6.2K]

Answer:  The required solution of the given differential equation is

y(x)=3e^{4x}-3e^{-4x}+2xe^{-4x}.

Step-by-step explanation:  We are given to solve the following differential equation :

y^{\prime\prime\prime}+4y^{\prime\prime}-16y^\prime-64y=0~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)\\\\\y(0)=0,~y^\prime(0)=26,~y^{\prim\prime}(0)=-16.

Let, y=e^{mx} be an auxiliary solution of equation (i).

Then, y^\prime=me^{mx},~~y^{\prime\prime}=m^2e^{mx},~~y^{\prime\prime\prime}=m^3e^{mx}.

Substituting these values in equation (i), we get

m^3e^{mx}+4m^2e^{mx}-16me^{mx}-64e^{mx}=0\\\\\Rightarrow (m^3+4m^2-16m-64)e^{mx}=0\\\\\Rightarrow m^3+4m^2-16m-64=0,~~~~~~~~~[\textup{since }e^{mx}\neq 0]\\\\\Rightarrow m^2(m-4)+8m(m-4)+16(m-4)=0\\\\\Rightarrow (m-4)(m^2+8m+16)=0\\\\\Rightarrow (m-4)(m+4)^2=0\\\\\Rightarrow m-4=0,~~(m+4)^2=0\\\\\Rightarrow m=4,~m=-4,~-4.

So, the general solution is given by

y(x)=Ae^{4x}+Be^{-4x}+Cxe^{-4x}.

Then, we have

y^\prime=4Ae^{4x}-4Be^{-4x}-4Cxe^{-4x}+Ce^{-4x},\\\\y^{\prime\prime}=16Ae^{4x}+16Be^{4x}+16Cxe^{-4x}-4Ce^{-4x}-4Ce^{-4x}\\\\\Rightarrow y^{\prime\prime}=16Ae^{4x}+16Be^{4x}+16Cxe^{-4x}-8Ce^{-4x}.

With the conditions given, we get

y(0)=A+B+C\times 0\\\\\Rightarrow A+B=0\\\\\Rightarrow A=-B~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(ii)

y^\prime(0)=4A-4B+C\\\\\Rightarrow 4A-4B+C=26\\\\\Rightarrow 4(A+A)+C=26~~~~~~~~~~~~~~~~[\textup{using equation (i)}]\\\\\Rightarrow C=26-8A~~~~~~~~~~~~~~~~~~~~~~~~~~~(iii)

and

y^{\prime\prime}(0)=16A+16B-8C\\\\\Rightarrow 16A-16A-8C=-16~~~~~~~~~~~~[\textup{using equation (ii)}]\\\\\Rightarrow -8C=-16\\\\\Rightarrow C=2.

From equation (iii), we get

C=26-8A\\\\\Rightarrow 2=26-8A\\\\\Rightarrow 8A=24\\\\\Rightarrow A=3.

From equation (ii), we get

B=-3.

Therefore, the required solution of the given differential equation is

y(x)=3e^{4x}-3e^{-4x}+2xe^{-4x}.

4 0
3 years ago
A chemist examines 15 geological samples for potassium chloride concentration. The mean potassium chloride concentration for the
Lelu [443]

Answer:

95% Confidence interval: (0.375,0.377)

Step-by-step explanation:

We are given the following in the question:

Sample mean, \bar{x} = 0.376 cc/cubic meter

Sample size, n = 15

Alpha, α = 0.05

Sample standard deviation, s = 0.0012

Degree of freedom =

=n-1\\=15-1\\=14

95% Confidence interval:  

\bar{x} \pm t_{critical}\displaystyle\frac{s}{\sqrt{n}}  

Putting the values, we get,  

t_{critical}\text{ at degree of freedom 14 and}~\alpha_{0.05} = \pm 2.145  

0.376 \pm 2.145(\dfrac{0.0012}{\sqrt{15}} )\\\\ = 0.376 \pm 0.0006\\\\ = (0.3754,0.3766)\approx (0.375,0.377)  

(0.375,0.377) is the required 95% confidence interval for the population mean potassium chloride concentration.

5 0
3 years ago
If 56% of people own a dog and 5 people are chosen at random, what is the probability that at least one person owns a dog?
wariber [46]

Answer:

2.8

Step-by-step explanation:

we do 56% times 5= 2.8

so 2.8 is your answer

(this answer was given by my friend who claims this is true.)

4 0
2 years ago
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