Joe will build a rectangular pen for his dog. A wall will form one side of the pen. Joe has 40 ft of fencing to form the other t hree sides. Joe plans to build the pen so that it has its maximum possible area.
What will be the dimensions of Joe’s dog pen?
2 answers:
Material=wall+2*side and material is 40 ft so: 40=w+2s w=40-2s Area=ws, using w from above we get: A=(40-2s)s A=40s-2s^2 dA/ds=40-4s and d2A/ds2=-4 Since d2A/ds2 is a constant negative acceleration, when dA/ds=0, A(s) is at an absolute maximum. dA/ds=0 when 4s=40, s=10 ft And since w=40-2s, w=20 ft So the dimensions of the pen are 20 ft by 10 ft, with the 20 ft side being opposite the wall. And the maximum possible area is thus 200 ft^2
Answer:
The <em>dimensions</em> are 20 ft by 10 ft.
Step-by-step explanation:
I just took this quiz and put the answer 200 by 200 ft. And I got it wrong because they asked for the dimensions. The other person's answer is correct, but in the wrong form! Thanks for the help and support on brainly!!!
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