Question

Write the equation of the line that passes through (–1, 5) and has a slope of 3 in point-slope form.

Answer 1

Answer:  $y-5=3(x+1)$

Step-by-step explanation:

By definition the equation of the line written in point-slope form is the following:

$y-y_1=m(x-x_1)$

Where ($x_1,y_1$) is a point of the line and m is the slope.

You know that the slope is 3 and the ine that passes through (-1, 5).

Then, when you substitute these values into the equation, you obtain:

  $y-5=3(x-(-1))$

 $y-5=3(x+1)$

Answer 2

Answer:

y - 5 = 3 (x + 1)

Step-by-step explanation:

Start with the pertinent equation of a straight line:  the point-slope form:

y-k = m(x-h), where (h,k) is the given point and m is the given slope.

Then y - 5 = 3(x-(-1) ), or y - 5 = 3 (x + 1).