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goblinko [34]
3 years ago
12

Perform the operation. enter your answer as in scientific notation 9×10²-5.6×10²

Mathematics
1 answer:
algol [13]3 years ago
6 0
The answer is 340, not super good at math so dont know what scientific notation is but there you go
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There are mangoes and oranges in a basket in the ratio 7: 11. If the total number of fruits is 720, then how many mangoes are th
lbvjy [14]

Answer:

280 mangoes

Step-by-step explanation:

sum the parts of the ratio, 7 + 11 = 18 parts

Divide the total by 18 to find the value of one part of the ratio.

720 ÷ 18 = 40 ← value of 1 part of the ratio , then

7 × 40 = 280 ← number of mangoes

8 0
2 years ago
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A scatter plot was made to show the value of certain cars based on the age of the car in years. The equation of the scatter plot
Mashutka [201]
Am not sure but I think it C
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3 years ago
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What’s the rate of change of the table above? <br> A) -1/3<br> B) 1/2<br> C) -1/4<br> D) 1/5
insens350 [35]

answer is option D

because you can divide them like

\frac{2}{10}  =  \frac{1}{5}  \\  \\  \frac{4}{20}  =  \frac{1}{5}  \\  \\  \frac{6}{30}  =  \frac{1}{5}  \\  \\  \frac{8}{40}  =  \frac{1}{5}

so the option is D

please mark this answer as brainlist

3 0
2 years ago
What is the surface area of the square pyramid?
Liula [17]

Answer:

16

Step-by-step explanation:

2^2+4(\frac{1}{2}\cdot  2\cdot 3)=4+12=16 square units. Hope this helps!

3 0
3 years ago
two mountain bikers leave from the same parking lot and head in opposite directions on two different trails. the first rider goe
sveta [45]

Applying the required <em>rule </em>or <em>theorem</em>, it can be concluded that the second biker is <u>farther</u> from the <em>parking lot</em>. The distance of the bikers to the <em>parking lot</em> are:

i. First biker = 17.0 km

ii. Second biker = 20.22 km

The <u>path</u> of travel of both bikers would form a triangle. Applying the <u>Pythagoras</u> theorem to the path of the <em>first</em> biker would give his <u>distance</u> from the starting point. While applying the <u>cosine</u> rule to the path of <em>second</em> rider would gives his <u>distance</u> to the starting point.

Thus,

a. <u>To determine the distance of the first biker from the parking lot.</u>

Let the required <em>distance </em>be represented by x. Applying the Pythagoras theorem, we have:

hyp^{2} = adj 1^{2} + adj 2^{2}

x^{2} = 8^{2} + 15^{2}

   = 64 + 225

   = 289

x = \sqrt{289}

  = 17

x = 17 km

Thus, the <u>first</u> biker is 17.0 km from the <em>starting</em> point.

b. <u>To determine the distance of the second biker from the parking lot.</u>

Let the required <em>distance</em> be represented by x. So that applying the cosine rule, we have:

c^{2} = a^{2} + b^{2} - 2ab Cos θ

x^{2} = 8^{2} + 15^{2} - 2(15*8) Cos (180 - 20)

    = 64 + 225 - 240 Cos 160

    = 289 - 240 * -0.5

x^{2} = 289 + 120

   = 409

x = \sqrt{409}

 = 20.2237

x = 20.22 km

Thus, the <u>second</u> biker is 20.22 km from the <em>starting</em> point.

Therefore, the second biker is <u>farther</u> from the <em>parking lot</em>.

A sketch of the path of travel for the two bikers is attached for more clarifications.

Visit: brainly.com/question/22699651

7 0
2 years ago
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