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charle [14.2K]
3 years ago
10

Find the range of f(x) = -x + 4 for the domain (-3,-2,-1,1).

Mathematics
1 answer:
timofeeve [1]3 years ago
4 0
The domain: D={-3;-2;-1; 1}

f(x) = -x + 4

subtitute

f(-3) = -(-3) + 4 = 3 + 4 = 7
f(-2) = -(-2) + 4 = 2 + 4 = 6
f(-1) = -(-1) + 4 = 1 + 4 = 5
f(1) = -1 + 4 = 3

Answer: The range: {3; 5; 6; 7}
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Answer:

a=14

Step-by-step explanation:

-a+28=14

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so a=14

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54/3-7=11

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x/3<u>-7=11</u>

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If y varies directly as x and y = 36 when x = 4,what is the constant of variation?​
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Step-by-step explanation:

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What is the equation of the following line? Be sure to scroll down first to see
Rom4ik [11]
<h2>Answer:</h2>

-1/3x

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<h3>Asked :</h3>
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<h3>Solution :</h3>

We can find the straight line equation using this formula,

\frac{y-y1}{y2-y1} = \frac{x-x1}{x2-x1}

Insert all we know inside the formula,

\frac{y-1}{0-1} = \frac{x-(-3)}{0-(-3)}\\\frac{y-1}{-1} = \frac{x +3}{3}\\

Use cross multiplication,

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3y = -x

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<h3>Conclusion :</h3>

The correct equation is y = -1/3x

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