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sdas [7]
3 years ago
15

I need help with this!

Mathematics
1 answer:
monitta3 years ago
5 0
Eeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeee
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F(x)=7x^2-8+9x^4÷x+2
kifflom [539]
Im pretty sure tge answers -1.68426




4 0
3 years ago
Find the value of x.<br><br> help pls !
Ad libitum [116K]

Answer:

68

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
gabriella wants to tile a room with an area of 320 square feet. the width of the room is 4/5 its length. what are the length and
Salsk061 [2.6K]
Assuming the shape of the room is a rectangle :

Area = Width x Length.

Let's call width "w" and length "l" . Now if, the width is 4/5 of the length that means 4/5 times length gives us the width, like this :

w=\frac { 4 }{ 5 } \cdot l

As given in the question, area of the rectangle is 320 square feet. And as I said before area of a rectangle can be found by multiplying its length and width. 

w.l=320

w=\frac { 4 }{ 5 } \cdot l , we can plug w's value in the previous equation to find "l". 

\frac { 4 }{ 5 } \cdot l\cdot l=320\\ \\ \frac { 4 }{ 5 } \cdot { l }^{ 2 }=320\\ \\ { l }^{ 2 }=320\cdot \frac { 5 }{ 4 } \\ \\ { l }^{ 2 }=\frac { 320\cdot 5 }{ 4 } \\ \\ { l }^{ 2 }=\frac { 1600 }{ 4 } \\ \\ { l }^{ 2 }=400\\ \\ \sqrt { { l }^{ 2 } } =\sqrt { 400 } \\ \\ l=20

Let's plug "l"s value in the equation.

w.l=320\quad \Longrightarrow \quad w\cdot 20=320\quad \Longrightarrow \quad w=\frac { 320 }{ 20 } \quad \Longrightarrow \quad w=16

The length is 20 feet and the width is 16 feet.


6 0
3 years ago
Read 2 more answers
Type the number of years in a century.
Fiesta28 [93]
One Hundred Years is the number of years in a century

6 0
3 years ago
I have a Triangle and I need to find the side BC?
Rus_ich [418]
Looking at this problem in the book, I'm guessing that you've been
introduced to a little bit of trigonometry.  Or at least you've seen the
definitions of the trig functions of angles.

Do you remember the definition of either the sine or the cosine of an angle ?

In a right triangle, the sine of an acute angle is  (opposite side) / (hypotenuse),
and the cosine of an acute angle is (adjacent side) / (hypotenuse).

Maybe you could use one of these to solve this problem, but first you'd need to
make sure that this is a right triangle.

Let's see . . . all three angles in any triangle always add up to 180 degrees.
We know two of the angles in this triangle ... 39 and 51 degrees.
How many degrees are left over for the third angle ?
180 - (39 + 51) = 180 - (90) = 90 degrees for the third angle.
It's a right triangle !  yay !  We can use sine or cosine if we want to.

Let's use the 51° angle.
The cosine of any angle is (adjacent side) / (hypotenuse) .
'BC' is the side adjacent to the 51° angle in the picture,
  and the hypotenuse is 27 .

cosine(51°) = (side BC) / 27

Multiply each side of that equation by 27 :

Side-BC = (27) times cosine(51°)

Look up the cosine of 51° in a book or on your calculator.

Cosine(51°) = 0.62932 (rounded)

<u>Side BC</u> = (27) x (0.62932) = <u>16.992</u> (rounded)
============================================

You could just as easily have used the sine of 39° .
That would be (opposite side) / (hypotenuse) ... also (side-BC) / 27 .
4 0
3 years ago
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