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Strike441 [17]
3 years ago
15

Please help with 6th grade math

Mathematics
1 answer:
Lady_Fox [76]3 years ago
6 0

Answer:

"1.03 yards per square foot"

Step-by-step explanation:

5.15 yd                     1.03 yd

----------- becomes  ------------- , or "1.03 yards per square foot."  That's a unit

5 ft^2                          ft^2                                                                  rate.

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How is Demoragan's law used in logic ?
Mekhanik [1.2K]

Answer:

Step-by-step explanation:

In propositional logic and Boolean algebra, De Morgan's laws are a pair of transformation rules that are both valid rules of inference. ... The rules allow the expression of conjunctions and disjunctions purely in terms of each other via negation.

4 0
3 years ago
Read 2 more answers
Can anyone help me solve this?​
Alecsey [184]

Answer:

Step-by-step explanation:

(\sqrt{z} +\sqrt{22})(\sqrt{z} -\sqrt{22})=35

Subtract both sides from 35

(\sqrt{z}+\sqrt{22} (\sqrt{z} -\sqrt{22})-35=35-35

Simplify:

(\sqrt{z})^{2} -57=0

Factor (\sqrt{z})^{2}  -57: (\sqrt{z}+\sqrt{57}) (\sqrt{z}-\sqrt{57})=0

\sqrt{z} +\sqrt{57}=0    or    \sqrt{z}  -\sqrt{57}=0

\sqrt{z} +\sqrt{57} =0: No Solution for Z

\sqrt{z} -\sqrt{57} =0: z=57

Your answer will be z=57

and No solution

8 0
2 years ago
Read 2 more answers
1. Let L be a list of numbers in non-decreasing order, and x be a given number. Describe an algorithm that counts the number of
e-lub [12.9K]

Answer:

Algorithm

Start

Int n // To represent the number of array

Input n

Int countsearch = 0

float search

Float [] numbers // To represent an array of non decreasing number

// Input array elements but first Initialise a counter element

Int count = 0, digit

Do

// Check if element to be inserted is the first element

If(count == 0) Then

Input numbers[count]

Else

lbl: Input digit

If(digit > numbers[count-1]) then

numbers[count] = digit

Else

Output "Number must be greater than the previous number"

Goto lbl

Endif

Endif

count = count + 1

While(count<n)

count = 0

// Input element to count

input search

// Begin searching and counting

Do

if(numbers [count] == search)

countsearch = countsearch+1;

End if

While (count < n)

Output count

Program to illustrate the above

// Written in C++

// Comments are used for explanatory purpose

#include<iostream>

using namespace std;

int main()

{

// Variable declaration

float [] numbers;

int n, count;

float num, searchdigit;

cout<<"Number of array elements: ";

cin>> n;

// Enter array element

for(int I = 0; I<n;I++)

{

if(I == 0)

{

cin>>numbers [0]

}

else

{

lbl: cin>>num;

if(num >= numbers [I])

{

numbers [I] = num;

}

else

{

goto lbl;

}

}

// Search for a particular number

int search;

cin>>searchdigit;

for(int I = 0; I<n; I++)

{

if(numbers[I] == searchdigit

search++

}

}

// Print result

cout<<search;

return 0;

}

8 0
3 years ago
Which shows this price as a correct unit price? $3.60 for 4 watermelons.
Ganezh [65]

Answer:

$0.90

Step-by-step explanation:

You are solving for the price of one watermelon (a unit of watermelon).

What is given to you is the price of 4 watermelons, or $3.60. To solve, simply divide $3.60 with 4:

3.60/4 = 0.90

$0.90 is your answer.

Remember to add the hundredth place value (0), as money goes to the hundredth place value.

~

7 0
3 years ago
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Eli packed 1,920 peanuts into 8 sacks. He packed an equal number of peanuts in each sack. How many peanuts did he pack into each
svlad2 [7]
D because one thousand nine hundred twenty divided by 8 equals two hundred and forty
8 0
2 years ago
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