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inysia [295]
4 years ago
8

A software designer is mapping the streets for a new racing game. All of the streets are depicted as either perpendicular or par

allel lines. The equation of the lane passing through A and B is -7x + 3y = -21.5. What is the equation of the central street PQ?
A.
-3x + 4y = 3

B.
-1.5x − 3.5y = -31.5

C.
2x + y = 20

D.
-2.25x + y = -9.75
Mathematics
1 answer:
Verizon [17]4 years ago
4 0
I think that the answer is letter a
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You can honestly find it your self your probably failing your class
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contestants in a dance-a-thon rest for the same amount of time every hour.a couple rests for 49 minutes in 7 hours.how long did
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PLEASE HELP I NEED 2 EQUATIONS!!! A food truck sells salads for $6.50 each and drinks for $2.00 each. The food truck’s revenue f
goldenfox [79]

Answer:

S = # of salads

d = # of drinks

$6.5s + $2d = $836.5

s + d =209

1. Isolate a variable.

s = 209-d

2. Plug in.

6.5 (209-d) + 2d = 836.5

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Step-by-step explanation:

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Today’s low temperature of 50.7 F came just dawn. During the day, the temperature increased 23.9F. What was Tuesday high tempera
raketka [301]
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4 0
3 years ago
In the diagram below of right triangle KMI, altitude IG is drawn to hypotenuse KM.
Yanka [14]

The length of GM is 16. It is obtained from the right triangle KMI, altitude IG is drawn to hypotenuse KM and KG = 9 and IG= 12.

Step-by-step explanation:

The given is,

                  Right triangle KMI

                  KG = 9

                  IG= 12

Step:1

                From the triangle KMI,

                           90° = ∅_{1} + ∅_{2}.................................(1)

                From the triangle KGI,

                Trignometric ratio,

                          tan ∅_{1} = \frac{Opp}{Adj}.................................(2)

                Where, Opp = 9

                               Adj = 12

               Equation (2) becomes,

                          tan ∅_{1} = \frac{9}{12}

                                     = 0.75

                                 ∅_{1} = tan^{-1} 0.75

                                 ∅_{1} = 36.87°

              From the equation (1),

                                 ∅_{2} =  90° - ∅_{1}

                                      = 90° - 36.87°

                                ∅_{2} = 53.13°

             From the triangle IGM,

                           tan ∅_{2} = \frac{Opp}{Adj}..........................(3)

              Where, Opp = GM

                             Adj = 12

                               ∅_{2} = 53.13°

             Equation (2) becomes,

                   tan 53.13° = \frac{GM}{12}

                             GM = (1.333)(12)

                                    = 15.999

                             GM ≅ 16

Result:

            The length of GM is 16. It is obtained from the right triangle KMI, altitude IG is drawn to hypotenuse KM and KG = 9 and IG= 12.

           

6 0
4 years ago
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