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ladessa [460]
3 years ago
11

Solving each system by eliminating x-y+z= -1 x+y+3z= -3 2x-y+2z= 0

Mathematics
1 answer:
Pie3 years ago
4 0

There's only one system of equations here.

Let's eliminate x first,

x - y + z = -1

x = -1 + y - z

Substituting into  x + y + 3z = -3 gives

(-1 + y - z) + y + 3z = -3

2y + 2z = -2

y + z = -1

Substituting for x into 2x-y+2z = 0 gives

2(-1 + y - z) - y + 2z = 0

-2 + 2y - 2z - y + 2z = 0

y = 2

Got lucky on that one.  

z = -1 - y = -1 - 2 = -3

x = -1 + y - z = -1 + 2  - -3 = 4

Answer: x=4, y=2, z= -3

Check:

x-y+z = 4 - 2 + -3 = -1, good

x+y+3x = 4+2+3(-3) =  -3, good

2x-y+2x = 2(4)-2+2(-3) = 0, good

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kobusy [5.1K]

The equation of the line is y - 3 = 5(x - 8) ⇒ c

Step-by-step explanation:

The point-slope form of the linear equation is y-y_{1}=m(x-x_{1}) , where:

  • m is the slope of the line
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∵ The line passes through point (8 , 3)

∴ x_{1} = 8 and y_{1} = 3

∵ The slope of the line is 5

∴ m = 5

- Substitute these values in the form of the equation below

∵ y-y_{1}=m(x-x_{1})

∴ y - 3 = 5(x - 8)

The equation of the line is y - 3 = 5(x - 8)

Learn more:

You can learn more about the linear equations in brainly.com/question/1284310

#LearnwithBrainly

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