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ollegr [7]
2 years ago
6

Evaluate the expression (4p - m) where m=-4 and p=2 Show the work plz.

Mathematics
2 answers:
frutty [35]2 years ago
7 0

Answer:

Step-by-step explanation:

m = - 4   & p =2

4p - m = 4*2 - (-4)

            = 8 + 4

            = 12

shusha [124]2 years ago
6 0

Answer:

12

Step-by-step explanation:

(4p - m)

Let m = -4 and p=2

( 4* 2 - (-4))

Multiply

8 - -4

Add

8+4

12

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The measure of the  largest exterior angle of hexagon is 105

<u>Solution:</u>

Given, The measures of 5 of the Interior angles of a hexagon are: 115.125", 85", 150", and 170".  

We have to find what is the measure of the largest exterior angle?  

Now let us find the 6th interior angle,  

We know that, sum of interior angles of hexagon = 720 degrees

115 + 125 + 85 + 150 + 170 + 6th angle = 720

645 + 6th angle = 720  

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3 years ago
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Step-by-step explanation:

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Complete the assignment on a separate sheet of paper<br><br> Please attach pictures of your work.
Irina18 [472]

Answer:

<u>TO FIND :-</u>

  • Length of all missing sides.

<u>FORMULAES TO KNOW BEFORE SOLVING :-</u>

  • \sin \theta = \frac{Side \: opposite \: to \: \theta}{Hypotenuse}
  • \cos \theta = \frac{Side \: adjacent \: to \: \theta}{Hypotenuse}
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<u>SOLUTION :-</u>

1) θ = 16°

Length of side opposite to θ = 7

Hypotenuse = x

=> \sin 16 = \frac{7}{x}

=> \frac{7}{x} = 0.27563......

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2) θ = 29°

Length of side opposite to θ = 6

Hypotenuse = x

=> \sin 29 = \frac{6}{x}

=> \frac{6}{x} = 0.48480......

=> x = \frac{6}{0.48480....} = 12.37599..... ≈ 12.3

3) θ = 30°

Length of side opposite to θ = x

Hypotenuse = 11

=> \sin 30 = \frac{x}{11}

=> \frac{x}{11} = 0.5

=> x = 0.5 \times 11 = 5.5

4) θ = 43°

Length of side adjacent to θ = x

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=> \cos 43 = \frac{x}{12}

=> \frac{x}{12} = 0.73135......

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5) θ = 55°

Length of side adjacent to θ = x

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6) θ = 73°

Length of side adjacent to θ = 8

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Length of side opposite to θ = 12

Length of side adjacent to θ = x

=> \tan 69 = \frac{12}{x}

=> \frac{12}{x} = 2.60508......

=> x = \frac{12}{2.60508....}  = 4.60636.... ≈ 4.6

8) θ = 20°

Length of side opposite to θ = 11

Length of side adjacent to θ = x

=> \tan 20 = \frac{11}{x}

=> \frac{11}{x} = 0.36397......

=> x = \frac{11}{0.36397....}  =30.22225.... ≈ 30.2

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